4/19 - Intro to Calculus - Check in

_{Evaluate the integral}

• 30/3
• 31/3
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• 32/3

 What is the value of the definite integral :   $\int_0^{\frac{\pi}{2}}\cos\left(x\right)\ dx$ 

• -1

• 1

•  $\pi$  

•  $\frac{\pi}{2}$  

 $\int_1^2\frac{1}{\left(4x-3\right)^2}dx=$  

• 15

•  $1.5$  

•  $-\frac{1}{5}$  

•  $\frac{1}{5}$  

Write the integral that would be used to find the area bounded by y = x² + 1, y = x - 2, x = -2 and x = 2.

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Find the second derivative of the function:
f (x) =  2x - 5x⁶

• f ''(x)= 2 - 30x
• f ''(x) =  2-30x⁵
• f ''(x) = -30x⁵
• f ''(x) = -150x⁴