Algebra 1 10.3-10.4 Review

Solve using square roots.

x² = 64

• x = 8, -8

• x = 32, -32

• x = 4, -4

• No real solution

Tags

TEKS.MATH.A.8A

Solve using square roots.

3x² - 27 = 0

• x = 4.9, -4.9

• x = 9, -9

• x = 3, -3

• No solution

Tags

TEKS.MATH.8.2B

Solve using square roots.

k² - 6 = 43

• k = √37

• k = 37 or - 37

• k = 7, k = -7

• no solution

Tags

TEKS.MATH.8.2B

Solve using square roots.
5b² - 4 = 41

• b = 9, b = -9
• b = 3, b = -3
• b = 8, b = -8
• no solution

Tags

TEKS.MATH.8.2B

Solve using square roots.
4m² - 100 = 0

• m=25, -25
• m=96
• m=5, -5
• m=-96

Tags

TEKS.MATH.8.2B

Solve using square roots.
 $x^2-15=0$  

•  $x=\pm15$  
  

•  $x=\pm3.87$  

•  $x=\pm7.5$  

• No Solution

Tags

TEKS.MATH.8.2B

Solve using square roots.
 $4x^2=25$  

•  $x=\pm\frac{5}{2}$  
  

•  $x=\frac{5}{2}$  
  

•  $x=-\frac{5}{2}$  

• no solution

Tags

TEKS.MATH.8.2B

Solve using square roots.
 $7x^2=-21$  

•  $x=\pm1.73$  

•  $x=\pm3$  
  

•  $x=\pm5.29$  

• no solution

Tags

TEKS.MATH.8.2B

What is the first step in solving

(x + 2)(x - 3) = 0 ?

• Plug in zero for x

• Solve for x

• FOIL

• Set each factor equal to zero

Tags

TEKS.MATH.A.8A

Solve for the values of x:

(x - 3)(x + 6) = 0

• x = -3, -6

• x = 3, -6

• x = -3, -6

• x = 3, 6

Tags

TEKS.MATH.A.8A