Two objects, object X and object Y , are held together by a light string and are released from rest near a planet’s surface in the orientation that is shown in the figure. Object X has a greater mass than object Y . A graph of the acceleration as a function of time for the system’s center of mass is shown for the 4s. The positive direction is considered to be upward. How does the speed of object Xvx compare to that of the system’s speed Vs after the objects have fallen for 4s?

The answer cannot be determined without knowing the relative masses of object X and object Y.

Car X and car Y travel on a horizontal surface along different parallel, straight paths. Each car’s velocity as a function of time is shown in the graph. Which of the following claims is correct about car X and car Y ?

Both car X and car Y travel in the same direction

Between t=6s and t=7s, car X and car Y are at the same horizontal position.

The change in car X's speed per unit of time increases as time increases and the change in car Y's speed per unit of time decreases as time increases.

The magnitude of the acceleration of car X is the same as the magnitude of the acceleration of car Y.

A student must design an experiment to determine the acceleration of a cart that rolls down a small incline after it is released from rest. The student has access to a timer, a meterstick, and a slow-motion camera that takes a photograph every 1/60 of a second. The angle that the incline makes with the horizontal is unknown, and the length of the incline is unknown. Which of the following procedures could the student use to determine the cart’s acceleration? Select two answers.

Use the timer to record the time it takes the cart to travel alongside a meterstick that is attached to the incline.

Use the slow-motion camera to film the cart as it rolls down the incline alongside a meterstick that is attached to the incline.

Use the meterstick to measure the vertical height of the incline, and use the timer to record the time it takes for the cart to travel down the incline.

Use the slow-motion camera to film the cart as it rolls down the incline alongside a timer that is attached to the incline.

Which of the following is a correct ranking of the normal forces Fn1, Fn2, and Fn3 exerted on the boxes?

The answer cannot be determined without knowing the masses of the boxes.

How does the magnitude of the force exerted by the stick on the puck Fpuck, stick compare to the magnitude of the force exerted by the puck on the stick Fstick, puck at the time interval in which the stick is in contact with the puck?

It cannot be determined because the masses of the puck and stick are unknown.

Which of the following statements best describes the force or forces exerted on the puck after it is hit by the stick and slides on the ice?

There is no frictional force exerted on the puck, and the gravitational force and normal force are exerted on the puck and are equal in magnitude.

The applied force from the stick is still exerted on the puck during this time

Since the puck's acceleration is zero, there are no forces exerted on the puck during this time.

Since there is no frictional force exerted on the puck, but the gravitational force is exerted on the puck

A falling skydiver opens his parachute. A short time later, the weight of the skydiver-parachute system and the drag force exerted on the system are equal in magnitude. Which of the following statements predicts the motion of the skydiver at thi time?

The skydiver is moving downward with constant speed.

The skydiver is moving downward with an upward acceleration

The skydiver is moving downward with a downward acceleration.

Consider a runner in any of the lanes moving at a known, constant tangential speed. Which of the following measuring tools, if any, could be used to experimentally determine the centripetal acceleration of the runner?

None of these measuring tools, by themselves, can be used with the known tangential speed to determine the centripetal acceleration of the runner.

MCQ Test Review

Authored by Alyssabeth A

Physics

11th Grade

NGSS covered

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MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Rock is released from rest at the top of a cliff that is on Earth. A short time later, Rock is released from rest
from the same location as Rock . Both rocks fall for several seconds before landing on the ground directly below
the cliff. Frictional forces are considered to be negligible.
Which of the following graphs correctly shows the vertical velocity of rock as a function of time? Take
the positive direction to be upward.

Tags

NGSS.HS-PS2-1

NGSS.HS-PS2-4

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following graphs best represents the vertical displacement of Rock as a function of time starting from immediately after the rock is released from rest? Take the positive direction to be downward.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After Rock is released from rest several seconds after Rock is released from rest, what happens to the separation distance between the rocks as they fall but before they reach the ground, and why? Take the positive direction to be downward.

is constant because at the moment Rock is released, the only difference between the rocks is their difference in height above the ground.

is constant because the difference in speed between the two rocks stays constant as they fall.

increases because the difference in speed between the two rocks increases as they fall.

increases because at all times Rock falls with a greater speed than Rock.

Tags

NGSS.HS-PS2-1

NGSS.HS-PS2-4

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Toy car travels across a horizontal surface with acceleration after starting from rest. A toy car travels across the same surface toward a car with acceleration after starting from rest. The car is separated from a car by a distance. Which of the following pairs of equations could be used to determine the location on the horizontal surface where the two cars will meet, and why?

X=Xo +VoXt+1/2Axt^2 for car W, and X=Xo+Voxt+1/2Axt^2 for car Z. Since the cars will meet at the same time, solving for in one equation and placing the new expression for into the other equation will

eliminate all unknown variables except.

X=Xo +VoXt+1/2Axt^2 for car W, and ∆X=X-Xo for a car Z. Since the separation distance is known between both cars, the displacement for a car Z can be used in the equation for car W so that the time at which the cars meet can be determined. Once known, the time can be used to determine the meeting location.

∆X=X-Xo for car W, and X=Xo +VoXt+1/2Axt^2 for a car Z. Since the separation distance is known between both cars, the displacement for a car W can be used in the equation for a car Z so that the time at which the cars meet can be determined. Once known, the time can be used to determine the meeting location.

∆X=X-Xo for car W, and ∆X=X-Xo for car Z Since the location at which the cars meet represents the final position of both cars, the separation distance for both cars can be substituted into both equations to determine the final position of both cars.

Tags

NGSS.HS-PS2-1