Solving with logs and exponential functions

Solve the equation for x

• 1.771

• 0.5646

• 1.6203

• 1.8456

Solve the equation for x

• 1.6023

• 0.7122

• 0.6477

• 1.544

Solve the equation for x

• 1.585

• 3.169

• 0.792

• 1.084

Solve for x

• 1.631

• 2.262

• 1.734

• 1.465

Solve $2^{\left(x+3\right)}=16$  

• -1

• 1

• 7

• 2

Solve for x:
2^x+6=2⁵

• -1
• 11
• 1
• -11

 $\log_4\left(3x+2\right)=3$  
Solve for x.

• 20.67

• 26.33

• 11

• 27.67

 $\log_6\left(x+5\right)+\log_6\left(4\right)=2$  
Solve for x. Enter only numbers in your answer.

 $\log_5\left(x^5\right)-\log_5\left(x^3\right)=2$  

Which of the follow best describes why  $x=-5$  is an extraneous solution to the equation above?

Hint: Try plugging in -5 and simplifying!

• -5 does not match the base of the logarithms.

• -5 is less than the output of the equation.

• Plugging in -5 for x results in a negative argument.

• Plugging in -5 for x results in a positive argument.

 $\ln\left(x^3+3x\right)-\ln\left(x\right)=4$  
Solve for x.

•  $x=99.98$  and  $x=-99.98$  (extraneous)

•  $x=99.98$  and  $x=-99.98$  , no extraneous solutions

•  $x=7.18$  and  $x=-7.18$  (extraneous)

•  $x=7.18$ and  $x=-7.18$  , no extraneous solutions