New Algebra One Review

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Write down: a=1, b=6, c=-13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

Tags

CCSS.HSA-REI.B.4B

Solve by factoring: x² = 7x + 18

• -7 and -18

• 9 and 2

• 9 and -2

• 2 and 7

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(x + 2)(x - 3) = 0

• { 2, 3 }
• { -2, -3 }
• { 2, 3 }
• { -2, 3 }

Tags

CCSS.HSA-REI.B.4B

Solve by factoring

• -4, 2

• -2, 4

• -16

• -4

Tags

CCSS.HSA-REI.B.4B

Add the polynomials:
(3x³+3x²–4x+5) + (x³–2x²+x–4)

• 4x³ + 1x² – 3x + 1
• 2x³ + 1x² - 5x + 9
• 6x³ + 1x - 1x² - 3
• 3x⁵ +1x - 1x⁵ - 3x

Tags

CCSS.HSA.APR.A.1

Multiply:
(4x+1)(5x−2)

• 20x² + 3x − 2
• 20x² − 11x + 5
• 20x² − 18x + 2
• 20x² − 3x − 2

Tags

CCSS.HSA.APR.A.1

(5x+2)(x²-3x+6)

• 5x³ - 17x² +24x +12
• 5x³ + 17x² - 24x +12
• 5x³ - 13x² + 24x +12
• 5x³ +13x² - 24x - 12

Tags

CCSS.HSA.APR.A.1

Multiply
(x+5)²

• x²+25
• x²-25
• x²+10x+25
• x²-10x+25

Tags

CCSS.HSA.APR.C.4

Simplify each expression.
(6b³ + 6 - b⁴) - (8b³ - 6b⁴ + 2)

• 4b⁴ - 2b³ + 7
• 5b⁴ - 2b³ + 4
• b⁴ - 2b³ + 7
• 5b⁴ - 2b³ + 7

Tags

CCSS.HSA.APR.A.1

 $Simplify:\ \ \frac{x^8y^{12}}{x^4y^{15}}$  

•  $\frac{x^4}{y^3}$  

•  $\frac{x^{12}}{y^3}$  

•  $x^{12}y^{27}$  

•  $\frac{y^3}{x^4}$  

Tags

CCSS.HSA.APR.A.1