Tree Diagrams, Independence, and Conditional Probability

If there are 3 red sections, 4 blue sections, and 1 green section on a spinner, then...

P(Red) =

Round your answer to 3 decimal spaces as necessary.

Tags

CCSS.7.SP.C.7B

If there are 3 red sections, 4 blue sections, and 1 green section on a spinner, then...

P(Blue) =

Round your answer to 3 decimal spaces as necessary.

Tags

CCSS.7.SP.C.7B

If there are 3 red sections, 4 blue sections, and 1 green section on a spinner, then...

P(Green) =

Round your answer to 3 decimal spaces as necessary.

Tags

CCSS.7.SP.C.7B

If there are 3 red sections, 4 blue sections, and 1 green section on a spinner, then...

P(Red ∩ Green) =

Round your answer to 3 decimal spaces as necessary.

If there are 3 red sections, 4 blue sections, and 1 green section on a spinner, then...

P(Blue ∩ Red) =

Round your answer to 3 decimal spaces as necessary.

If there are 3 red sections, 4 blue sections, and 1 green section on a spinner, then...

P(Green ∩ Blue) =

Round your answer to 3 decimal spaces as necessary.

If there are 3 red sections, 4 blue sections, and 1 green section on a spinner, then...

P(Green | Blue) =

Round your answer to 3 decimal spaces as necessary.

Tags

CCSS.HSS.CP.B.6

If there are 3 red sections, 4 blue sections, and 1 green section on a spinner, then...

Are the event green and blue independent? Select an answer and a justification.

• Yes

• No

• because P(A) = P(A|B)

• because P(A) ≠ P(A|B)

Tags

CCSS.HSS.CP.A.3