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Serie de fourier

Authored by Juan lopez

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Serie de fourier
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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

1.- Herramienta matemática utilizada para analizar funciones periódicas a través de la descomposición de dicha función en sumas infinitesimales

Análisis de Crammer

Análisis de Green

Análisis de Fourier

Análisis de Legendre

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

2.- Las funciones pares son las que cumplen con la siguiente condición:

f(x) = f(x)f\left(x\right)\ =\ f\left(x\right)

f(x) = f(x)f\left(x\right)\ =\ f\left(-x\right)

f(x) = f(x)f\left(-x\right)\ =\ -f\left(x\right)

f(x) = f(x)f\left(-x\right)\ =\ f\left(x\right)

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

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3.- En matemáticas la expresión siguiente se utiliza para representar a

Una serie de Legendre

Una serie de Fourier

Una serie de Morgan

Una serie de Crammer

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

4.- Las funciones impares son aquellas que cumplen con la siguiente condición:

f(x) = f(x)f\left(-x\right)\ =\ -f\left(x\right)

f(x) = f(x)f\left(x\right)\ =\ f\left(x\right)

f(x) = f(x)f\left(-x\right)\ =\ f\left(x\right)

f(x) = f(x)-f\left(x\right)\ =\ f\left(x\right)

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

5.- La serie de Fourier de una función definida en el intervalo (-p, p) o en el medio intervalo es:

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6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

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xsinx=112cosx+2n=2(1)n+1n21cos(nx)x\sin x=1-\frac{1}{2}\cos x+2\sum_{n=2}^{\infty}\frac{\left(-1\right)^{n+1}}{n^2-1}\cos\left(nx\right)

xsinx=213cosx+2n=2(1)n+1n21cos(nx)x\sin x=2-\frac{1}{3}\cos x+2\sum_{n=2}^{\infty}\frac{\left(-1\right)^{n+1}}{n^2-1}\cos\left(nx\right)

xsinx=115cosx+3n=2(1)n+1n21cos(nx)x\sin x=1-\frac{1}{5}\cos x+3\sum_{n=2}^{\infty}\frac{\left(-1\right)^{n+1}}{n^2-1}\cos\left(nx\right)

xsinx=119cosx+2n=2(2)n+1n21cos(nx)x\sin x=1-\frac{1}{9}\cos x+2\sum_{n=2}^{\infty}\frac{\left(-2\right)^{n+1}}{n^2-1}\cos\left(nx\right)

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

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x=n=12n(1)n+1sen(nx)x=\sum_{n=1}^{\infty}\frac{2}{n}\left(-1\right)^{n+1}sen\left(nx\right)

x=n=14n(2)n+1sen(nx)x=\sum_{n=1}^{\infty}\frac{4}{n}\left(-2\right)^{n+1}sen\left(nx\right)

x=n=19n(1)n+1sen(nx)x=\sum_{n=1}^{\infty}\frac{9}{n}\left(1\right)^{n+1}sen\left(nx\right)

x=n=12n(1)n+1sen(nx)x=\sum_{n=1}^{\infty}-\frac{2}{n}\left(1\right)^{n+1}sen\left(nx\right)

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