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三角函數基礎題

Authored by 施 雅寧

Mathematics

10th - 11th Grade

Used 19+ times

三角函數基礎題
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7 questions

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1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

設θ為銳角,若 tanθ= 53\frac{5}{3}  ,則= cosθ+sinθ4cosθ+sinθ=\frac{\cos\theta+\sin\theta}{4\cos\theta+\sin\theta}=  

 512\frac{5}{12}  

 817\frac{8}{17}  

 178\frac{17}{8}  

 817-\frac{8}{17}  

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

設cos100°=k,則以 k 表出 tan(-260°)=

k1k2\frac{k}{\sqrt{1-k^2}}

1k2\sqrt{1-k^2}

1k2k\frac{\sqrt{1-k^2}}{k}

1k2k-\frac{\sqrt{1-k^2}}{k}

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

如圖,圓內接四邊形ABCD,求 x

2

3

4

5

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

 (sin700°,cos700°)試問點\left(\sin700\degree,\cos700\degree\right)  在第幾象限?

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

一人於地面A點測得山頂的仰角為30°,此人向山的方向前進200公尺後到B點,又測得山頂的仰角為45°,則此山的高度為多少公尺?

100(3+1)100\left(\sqrt{3}+1\right)

200(31)200\left(\sqrt{3}-1\right)

2003200\sqrt{3}

100(6+2)100\left(\sqrt{6}+\sqrt{2}\right)

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

若∠B=85°,∠C=65°,a=20,則外接圓半徑為

10

 10310\sqrt{3}  

20

 20320\sqrt{3}  

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 sinθ+2sinθcosθ1+cosθ+cos2θsin2θ=\frac{\sin\theta+2\sin\theta\cos\theta}{1+\cos\theta+\cos^2\theta-\sin^2\theta}=  

 tanθ\tan\theta  

 sinθ\sin\theta  

 cosθ\cos\theta  

0

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