Quadratics in Standard, Vertex and Intercept Form Practice!

 Given $f\left(x\right)=2x^2+5-1$  , what is the vertex?

•  $\left(-\frac{5}{2},\ -\frac{31}{8}\right)$  

•  $\left(-\frac{5}{2},\ -\ \frac{35}{8}\right)$  

•  $\left(-\frac{5}{4},\ -\ \frac{35}{8}\right)$  

•  $\left(-\frac{5}{4},\ -\ \frac{33}{8}\right)$  

 $f\left(x\right)=2x^2+5x-1$  

Which way does the graph open and why?

• up because b > 0

• down because c < 0
  

• up because a > 0

Tags

CCSS.HSF-IF.C.7A

Given  $f\left(x\right)=\left(x+2\right)^2-3$   find the x-intercepts? (Hint: set y = 0 and solve for x by taking square roots)

•  $1-2\pm\sqrt{2}$  

•  $-2\pm\sqrt{5}$  

•  $-2\pm\sqrt{7}$  

•  $-2\pm\sqrt{3}$  

Tags

CCSS.HSA-REI.B.4B

Given  $f\left(x\right)=-\frac{1}{2}\left(x+4\right)\left(x+6\right)$  find the x-intercepts

• (-4,0) and (-6,0)

• (-4,0) and (6,0)

• (4,0) and (-6,0)

• (-4,0) and (6,0)

Tags

CCSS.HSA-SSE.B.3B

CCSS.HSF-IF.C.8A

Given $\frac{1}{2}\left(x-1\right)^2+2$  find the vertex

• (-1,2)

• (1,2)

• (1,-2)

• (-1,-2)

Given $f\left(x\right)=-\frac{1}{2}\left(x+4\right)\left(x+6\right)$  , find the axis of symmetry

• x = 5

• x = 8

• x = -5

• x = -8