1st quarter reviewer

• C(-15,16) and r=2√5

• C (-15,16) and r=2025

• C (-15,16) and r=45

• y=x²/288

• y = x²/72

• x=y²/288

• x=y²/72

Identify the center and the length of a and b.

• C: (0,4)  a= 25, b=4
• C: (0,0)  a= 4, b=25
• C: (0,5)  a= 2, b=5
• C: (0,0)  a= 5, b=2

Which is a horizontal ellipse?

• $\frac{x^2}{4}+\frac{y^2}{9}=1$

• $\frac{x^2}{16}+\frac{y^2}{9}=1$

• $\frac{x^2}{16}+\frac{y^2}{16}=1$

• $x^2+\frac{y^2}{49}=1$

What are the vertices of

 $\frac{x^2}{16}+\frac{y^2}{25}=1?$  

•  $\left(-4,\ 0\right)\ and\ \left(4,\ 0\right)$  

•  $\left(0,\ -4\right)\ and\ \left(0,\ 4\right)$  

•  $\left(-5,\ 0\right)\ and\ \left(5,\ 0\right)$  

•  $\left(0,\ -5\right)\ and\ \left(0,\ 5\right)$  

Check all the boxes that describe the ellipse

 $\frac{x^2}{4}+\frac{y^2}{81}=1$  

• The center is  $\left(0,0\right).$  

• The major axis is 81.

• The minor axis is 4.

• The graph is a horizontal ellipse.

What is the equation to get the foci of the ellipse?

• $c^2=a^2-b^2$

• $c^2=a^2+b^2$

• $c=\sqrt{a-b}$

• $c=\sqrt{a+b}$

What are the foci of the given ellipse?
 $\frac{x^2}{64}+\frac{y^2}{81}=1$  

•  $\left(-\sqrt{17},\ 0\right),\ \left(\sqrt{17},\ 0\right)$  

•  $\left(0,-\sqrt{17}\right),\ \left(0,\sqrt{17}\right)$  

•  $\left(0,\ -17\right),\left(0,17\right)$  

•  $\left(-17,0\right),\left(17,0\right)$  

What is the orientation of the hyperbola?

 $\frac{x^2}{4}-\frac{y^2}{25}=1$  

• vertical

• horizontal

What is the equation describing the relationship between dimensions and foci of a hyperbola?

• c² = a² + b²
• c² = a² - b²
• 4p
• (x-h)² + (y-k)² = r²