Variables on Both Sides with Distributive Property

Solve:
5y+34 = -2(-7y+1)

• y = -4

• y = 9

• y = 4

• y = 36/19

Tags

CCSS.6.EE.A.2

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

Solve the equation
12x - 15 = 3(2x+3)

• x = 4

• x = -4

• x = 2

• x = -2

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

Simplify 7(x - 1) = 23 + 10x

• -3

• -5

• -7

• -10

Tags

CCSS.6.EE.A.2

CCSS.6.EE.A.3

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

Which is the first step in simplifying 3(x - 5) = - 3x + 7 ?

• 3x - 5 = -3x + 7

• -3x - 15 = - 3x + 7

• 3x - 15 = 3x + 7

• 3x + 15 = 3x + 7

Tags

CCSS.6.EE.A.2

CCSS.6.EE.A.3

CCSS.6.EE.A.4

CCSS.6.EE.B.6

What is the first step you should take to solve this equation:

 $3\left(x-2\right)=2x+7$  

• Add 2 to both sides

• Use distributive property to get rid of the parentheses

• Isolate the variable on one side

• Subtract 7 from both sides

Check all that apply - What could you do to move the variable to one side of this equation:
 $2x+3=4x-7$ 

• Subtract 2x from both sides

• Subtract 3 from both sides

• Subtract 4x from both sides

• Add 7 to both sides

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

Solve the following equation for  $x.$ 

  $5x\ -\ 6\ =\ 8\ -\ 2x$  

•  $x\ =\ 2$  

•  $x\ =\ -4\ \frac{2}{3}$  

•  $x=\ -2$  

•  $x\ =-\frac{2}{3}$  

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

Jacob solved the following equation using the steps shown.

Step 1 5x + 9 = 2x - 3

Step 2 3x + 9 = -3

Step 3 3x = -12

Step 4 x = -4

What operation did he perform to get from Step 1 to Step 2?

• Subtracted 2x from both sides of the equation

• Subtracted 9 from both sides of the equation

• Multiplied both sides of the equation by 3

• Added -3 to both sides of the equation

Tags

CCSS.6.EE.A.3

The goal when solving an equation is to

• find what the variable is.

• check the solution.

• guess and check.

• combine like terms.

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.7

The Frederick County Fair costs $15.00 to get in and $2.50 per ride, while the Montgomery County Fair costs $10.00 to get in and $3.00 per ride. Which equations could be used to determine how many rides you would need to go on for both fairs to be of equal value?

• 15x + 2.5 = 10x + 3

• 15 - 2.5x = 10 - 3x

• 15 + 2.5x = 10 + 3x

• 15 - 10 = 2.5x + 3x

Tags

CCSS.6.EE.A.4

CCSS.6.EE.B.6

CCSS.6.EE.B.7

CCSS.6.EE.C.9