PROJECTILE MOTION RT

The vertical component of velocity of a projectile, during its motion, is minimum

• At the highest point of its trajectory

• At the point of projection

• Just before hitting the plane of projection

• None of these

The horizontal range is equal for the angles

• 0⁰ and 90⁰

• 45⁰ and 90⁰

• 30⁰ and 45⁰

• 30⁰ and 60⁰

The horizontal and the vertical components of the initial velocity of a projectile are 10 m/s and 20 m/s, respectively. The horizontal range of the projectile will be (g = 10 m/s^-2)

 

• 5m

• 10m

• 20m

• 40m

The angle of projection of a projectile is 30⁰. The ratio of the horizontal range and the maximum height is

• $4\sqrt{3}$

• $3\sqrt{4}$

• $2\sqrt{3}$

• $4\sqrt{2}$

If height of projectile is equal to range. The angle of projection is

• 45^o

• 76^o

• 60^o

• 90^o

The time of flight of a projectile is 10 seconds and its range is 500 m. The maximum height reached by it will be (g = 10 m/s²)

• 125 m

• 82 m

• 50 m

• 25 m

For a projectile, the ratio of maximum height reached to the square of flight time is (g = 10 m/s^-2)

• 5 : 2

• 5 : 4      

• 5 : 1

• 10 : 1

The time taken to achieve maximum height is given by

• t = v_oCosθ / g

• t = v_oSinθ / 2g

• t = v_oCosθ / 2g

• t = v_oSinθ / g

A ball is projected at an angle of 45⁰ to the horizontal. If the range is 10 m. The maximum height attained by the ball is (g = 10 m/s²)

 

• 1 m

• 2 m

• 2.5 m

• 3 m

The velocity of a projectile is maximum

• At half of the height

• At one-fourth of the height

• Just before striking the ground and point of projection

• None of these