Alg 2: 4.3 & 4.4 Review

Factor:

25x²-81

• (5x-9)²

• (5x+9)(5x-9)

• 25(x-9)²

• (9x+5)(9x-5)

3x⁴ - 48

• 3( x - 4) ( x + 4)(x²+4)

• 3( x - 2)(x+2) ( x² + 4)

• 3( x² - 8) ( x² + 8)

• 3( x - 4) ( x + 4)

Factor:  27x³ + 8

• (3x + 2)(9x² - 6x + 4)
• (9x + 2)(3x² + 18x + 4)
• (3x²+4)(9x + 2)
• (27x + 8)(x² - 216x + 64)

x³ - 1000

• (x + 10)(x² - 10x + 100)
• (x - 10)(x² + 10x + 100)
• (x - 1)(x² + 1x + 1)
• (x - 5)(x² + 5x + 25)

Is this division problem worked correctly?

• This is correct!
• This is incorrect!

Solve using long division. $\left(8x^2+6x-20\right)\div\left(4x-5\right)$  

•  $2x-4$  

•  $2x+4$  

•  $2x-1-\frac{16}{4x-5}$  

•  $2x-4-\frac{40}{4x-5}$ 

What is the remainder when you divide
 $\left(2x^3-5x-7\right)\ by\ \left(x+2\right)$  ?

• -9

• 11

• -13

• -1

(3x³ + 5x - 1) ÷ (x + 1)

• 3x³ - 3x² + 8x - 9

• $3x^2-3x+8-\frac{9}{x+1}$

• $3x^2+3x+8+\frac{7}{x+1}$

• 3x³ + 3x² + 8x + 7

Is (x-2) a factor of f(x)= x³-8x²+14x-4?

• Yes, (x-2) is a factor. There is a remainder.

• No, (x-2) is not a factor. The remainder is zero.

• Yes, (x-2) is a factor. The remainder is zero.

• No, (x-2) is not a factor. There is a remainder.

Factor: 20x³-25x²+4x-5

• (5x²-5)(4x+1)

• 5(x²-1)(4x+5)

• (5x²+1)(4x-5)

• (5x²+1)(4x-1)