AP Calculus AB: Graph Analysis

$$h\left(2\right)<h\ '\left(2\right)<h\ ''\left(2\right)$$  

$$h\ '\left(2\right)<h\left(2\right)<h\ ''\left(2\right)$$  

$$h\ ''\left(2\right)<h\left(2\right)<h\ '\left(2\right)$$  

$$h\ '\left(2\right)<h\ ''\left(2\right)<h\left(2\right)$$  

$$\left(-2,\infty\right)$$  

$$\left(-1,\infty\right)$$  

$$\left(-1,0\right)\cup\left(1,\infty\right)$$  

$$\left(-1,0\right)\cup\left(0,\infty\right)$$  

f has a local maximum at x = 2

f has a local maximum at $$x=-\frac{2}{3}$$  

f has inflection points at $$x=-\frac{2}{3}$$  and $$x=2$$  

f is increasing on the interval $$\left(-\frac{2}{3},2\right)$$  

$$\frac{3}{2}$$  

2

0

1

$$f\ '\left(x\right)$$  does not exist at x = 2.

f is decreasing on the interval

The graph of f has a point on inflection at x = 2.

f has a local maximum at x = 0.