Math 2 Review: Quadratics, Systems

Solve by factoring: x²-2x-35=0

• (-6,-8)
• (-7,5)
• (7,-5)
• (7,8)

Tags

CCSS.HSA-REI.B.4B

Solve by factoring: x²-13x+47=7

• (1,2)
• (1,-5)
• (-8,-5)
• (8,5)

Tags

CCSS.HSA-REI.B.4B

Solve using the Quadratic Formula: 12x²+4x-7=0

• (9±√301)/10
• (1/4,-7/12)
• 2±√11
• (-1±√22)/6

Tags

CCSS.HSA-REI.B.4B

Solve using the Quadratic Formula: 4x²+4x-16=0

• (±√38)/2
• (-1±√5)/2
• (-1±√17)/2
• (11≠√141)/2

Tags

CCSS.HSA-REI.B.4B

Identify the zero(s) from the graph.

• (0,3) (0,-1)

• (-3,0) (1,0)

• (0,-3) (0,1)

• (-1,0) (3,0)

Tags

CCSS.HSF-IF.C.7A

• a= 1, b= 2, c= -9

• a= 2, b= -1, c= 9

• a= -9, b= 2, c= -1

• a= -1, b= 2, c= -9

Select BOTH zeros of this parabola for full credit:

• (-1,-4)

• (-3,0)

• (1,0)

• (0,-3)

Tags

CCSS.HSF-IF.C.7A

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Write down: a=1, b=6, c=-13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

Tags

CCSS.HSA-REI.B.4B

Convert x²-6x+9 to factored form and identify the solution.

• (x-3)(x-3); x=3
• (x+3)(x+3); x=-3
• (x+4)(x+2); x=-4, -2
• Not factorable

Tags

CCSS.HSA-REI.B.4B

Solve the system of equations by substitution.

• (3, -24)

• (0, 4)

• (-24, 3)

• No solution

• Infinite solutions

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6