u substitution

$$\frac{\left(2x+5\right)^8}{8}+c$$  

$$\frac{\left(x^2+5\right)^8}{16}+c$$  

$$\frac{\left(x^2+5\right)^6}{6}+c$$  

$$\frac{\left(2x+5\right)^8}{16}+c$$  

$$\frac{\left(x^7-1\right)^9}{9}+c$$  

$$\frac{\left(x^7+1\right)^9}{9}+c$$  

$$\frac{\left(x^7+1\right)^8}{8}+c$$  

$$\frac{\left(7x^6+1\right)^9}{9}+c$$  

$$\frac{1}{2\sqrt{3+x^2}}+C$$  

$$\sqrt{3+x^2}+C$$  

$$2\sqrt{3+x^2}+C$$  

$$\frac{2}{\sqrt{3+x^3}}+C$$  

$$-\frac{1}{2\left(x^2+3\right)^2}+C$$  

$$-\frac{3}{2\left(x^2+3\right)^2}+C$$  

$$-\frac{5}{2\left(x^2+3\right)^2}+C$$  

$$-\frac{1}{\left(x^2+3\right)^4}+C$$  

$$7\left(\ln x\right)^7+C$$  

$$\frac{\ln^6x}{x^2}+C$$  

$$\frac{1}{7}\left(\ln x\right)^7+C$$  

$$\frac{6}{7}\left(\ln x\right)^7+C$$  

$$\ln\left(\ln x\right)+C$$  

$$\left(\ln x\right)^2+C$$  

$$\frac{1}{x^2}+C$$  

$$\frac{\ln x}{x^2}+C$$  

$$\frac{1}{9}\left(5+2x^3\right)^{\frac{3}{2}}+C$$  

$$\frac{2}{3}\left(5+2x^3\right)^{\frac{3}{2}}+C$$  

$$6x\left(5+2x^3\right)^{\frac{3}{2}}+C$$  

$$\frac{1}{9}x^3\left(5+2x^3\right)^{\frac{3}{2}}+C$$  

$$\frac{1}{2}\int_2^{10}u^3du$$  

$$\frac{1}{2}\int_{-1}^3u^3du$$  

$$\int_2^{10}u^3du$$  

$$2\int_2^{10}u^3du$$