квадрат теңсіздіктер

квадрат теңсіздіктер

8th Grade

10 Qs

quiz-placeholder

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квадрат теңсіздіктер

квадрат теңсіздіктер

Assessment

Quiz

Mathematics

8th Grade

Hard

Created by

Берик Калиев

Used 33+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

2.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

 (x216)(x2+1)0\left(x^2-16\right)\left(x^2+1\right)\le0  теңсіздігін шешіңіз.

 [4;4]\left[-4;4\right]  

 (:4)(4;)\left(-\infty:-4\right)\cup\left(4;\infty\right)  

 (:4][4;)\left(-\infty:-4\right]\cup\left[4;\infty\right)  

 (4;4)\left(-4;4\right)  

 [4;1][1;4]\left[-4;-1\right]\cup\left[1;4\right]  

3.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

 12xx+13>0\frac{12-x}{x+13}>0  теңсіздіктің бүтін шешімдерінің қосындысын табыңыз.

-12

-13

13

12

0

4.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

 x3x48x290\frac{x-3}{x^4-8x^2-9}\ge0  рационал теңсіздіктің шешімін табыңыз.

 (3;3][3;)\left(-3;3\right]\cup\left[3;\infty\right)  

 (3;3)\left(-3;3\right)_{ }  

 (1;3](9;)\left(-1;3\right]\cup\left(9;\infty\right)  

 (3;3)(3;)\left(-3;3\right)\cup\left(3;\infty\right)  

 (1;3](3;)\left(-1;-3\right]\cup\left(3;\infty\right)  

5.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

 y=x2+5x+4x29y=\sqrt{\frac{x^2+5x+4}{-x^2-9}}  Функцияның анықталу облысына тиісті бүтін сандардың қосындысын табыңыз

10

-10

 \infty  

-5

5

6.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

 (x1)(x+3)(x2)0 теңсіздікті шеш\left(x-1\right)\left(x+3\right)\left(x-2\right)\le0\ теңсіздікті\ шеш  

 [3;1][2;)\left[-3;1\right]\cup\left[2;\infty\right)  

 (;3)(1;2)\left(-\infty;-3\right)\cup\left(1;2\right)  

 (;2][1;3]\left(-\infty;-2\right]\cup\left[-1;3\right]  

 (;3][1;2]\left(-\infty;-3\right]\cup\left[1;2\right]  

 (3;1)(2;)\left(-3;1\right)\cup\left(2;\infty\right)  

7.

MULTIPLE CHOICE QUESTION

10 mins • 1 pt

 (x+2)2(x+5)(x1)(x+4)0 теңсіздікті шеш\left(x+2\right)^2\left(x+5\right)\left(x-1\right)\left(x+4\right)\ge0\ теңсіздікті\ шеш  

 [5;4]{2}[1;)\left[-5;-4\right]\cup\left\{-2\right\}\cup\left[1;\infty\right)  

 [5;4][1;)\left[-5;-4\right]\cup\left[1;\infty\right)  

 [5;4][2;1][1;)\left[-5;-4\right]\cup\left[-2;1\right]\cup\left[1;\infty\right)  

 [5;4][2;1]\left[-5;-4\right]\cup\left[-2;1\right]  

 (;)\left(-\infty;\infty\right)  

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