Exam Review 4

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Solve for the values of x:
(x + 2)(x - 3) = 0

• { 2, 3 }
• { -2, -3 }
• { 2, 3 }
• { -2, 3 }

Solve for the values of x:
(2x - 1)(x + 4) = 0

• { 1/2, -4 }
•  { 1/2, 4 }
• { 2, -4 }
• { -2, 4 }

Solve and find your x-intercepts:
0=x(x - 6)

• x=0 and x=-6
• x=1 and x=-6
• x=0 and x=6
• x=6

Solve and find your zeros:
z(z - 15)=0

• z=0 and z=15
• z=0 and z=-15
• z=-15
• z=15

Factor: x² – 5x – 24

• (x - 5)(x + 19)
• (x - 8)(x + 3)
• (x - 3)(x + 8)
• (x - 19)(x + 5)

Factor
12x + 9

• 3(4x + 3)
• x(12+9)
• 3(4x - 3)
• not factorable

(x - 5)(x - 2) = 0

• x = -5 and 2

• x = 5 and 2

• x = 5 and -2

• x = -5 and -2

Factor the Trinomial:
x² - 8x + 15

• (x + 5) ( x + 3)
• (x - 5) (x - 3)
• (x + 15) (x - 1)
• (x - 7) (x - 8)

Factor
x² + 12x + 36

• (x + 6)(x +6)
• (x + 9)(x - 4)
• (x - 12)(x + 3)
• (x - 6)(x - 6)