Factor Quadratics

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This questions is already factored for you. What is your next step?  (x + 2)(x - 3) = 0      

• Plug in zero for x
• Solve for x
• Set each binomial factor equal to zero

Solve for the values of x:
(x + 2)(x - 3) = 0

• { 2, 3 }
• { -2, -3 }
• { 2, 3 }
• { -2, 3 }

Find the solutions to this equation.

5x ( 7x - 3 ) = 0

• x = 0 and x = 3 / 7

• x = 0 and x = - 3 / 7

• x = 0 and x = 7 / 3

• x = -5 and x = 3 / 7

Solve using the Zero-Product Property.

7x(x − 6) = 0

• x =7 and x = −6

• x = 0 and x = 6

• x = 0 and x = −6

• x = 7 and x = 6

Solve for x

x(x-4)=0

• x=0

  x=4

• x=0

  x= -4

• x=1

  x=4

• x= -1

  x= -4

Solve by factoring: x² - 9x + 20 = 0

• x = -4 and x = -5

• x = 20 and x = -9

• x = 4 and x = 5

• x = -4 and x = 5

Solve by factoring: x² + 3x - 18 = 0

• x = -3 and x = 6

• x = 3 and x = -6

• x = -9 and x = 2

• x = 9 and x = -2