5.3 Solving Polynomial Equations

Factor:

Tags

CCSS.HSA.APR.C.4

Solve!

Tags

CCSS.HSA-REI.B.4B

Factor by grouping
x³ - 4x² -4x + 16

• (x+4)(x+2)
• (x-4)(x+2)(x-2) 

• (x+4)(x+2)(x-2)

• (x-4)(x-2)

Factor by grouping:
4p³+8p²+3p+6

• (2p²+3)(p+2)
• (2p²+6)(p+4)
• (4p²+3)(p+2)
• (4p²+8p)(3p+6)

Find all zeros for the polynomial
P(x) = x³ -3x²-5x+15

• 3, √5 
• 3, √5, -√5
• -3, √5, -√5
• -3, 5i, -5i

Factor this difference of cubes:
x³ - 343

• (x + 7)(x² - 7x + 49)

• (x - 7)(x - 7)(x - 7)

• (x - 7)(x² + 7x + 49)

• (x + 7)(x + 7)(x + 7)

Tags

CCSS.HSA.APR.C.4

The quadratic equation can be used to solve quadratic equations that cannot be factored.

• True
• False

Tags

CCSS.HSA-REI.B.4B