BSA Practice Math Test 1

• 4,342

• 5,042

• 5,082

• 5,382

Tags

CCSS.4.NBT.B.5

4,385 – 1,479

• 2,906

• 2,105

• 1,214

• 916

Tags

CCSS.4.NBT.B.4

1255 ÷ 25

• 125.2

• 75.5

•   50.2

• 25.5

Tags

CCSS.5.NBT.B.6

CCSS.6.NS.B.2

There are 1,520 students in a school.  The principal wants to give each student two peppermints to have for the state test.  Peppermints come in packages of 25 each.  How many packages need to be purchased?

• 60

• 61

• 122

• 123

Answer explanation

This problem requires division. The answer to the division is 60.8. You'll need to buy 61 bags because 60 bags would not be enough mints.

Tags

CCSS.5.NBT.B.6

CCSS.6.NS.B.2

Answer explanation

You had to find the common denominator before you can add or subtract. In this case, the common denominator is 40. Remember that when you change the denominator, you must change the numerator too.

Tags

CCSS.7.NS.A.1C

Answer explanation

You had to find the common denominator to subtract. 1/2 is equal to 8/16.

7 8/16 - 1/16= 7 7/16

Tags

CCSS.7.NS.A.1C

• 1

• 9

Tags

CCSS.4.NF.B.4B

CCSS.4.NF.B.4C

• 2

Answer explanation

1/2 divided by 2/8, requires you to multiply by the reciprocal of the second term. 1/2 times 8/2 = 8/4=2

Tags

CCSS.6.NS.A.1

• 18

• 9

• 6

• 4

Answer explanation

Keep it, switch it, flip it for division.

6/1 x 3/2 = 18/2 = 9

Tags

CCSS.5.NF.B.7B

CCSS.5.NF.B.7C

 Sarah went to the store with $18.50.  She bought three bracelets that cost $3 each.  How much money did she have left?

• $18.20

• $15.50

• $9.50

• $3.50

Answer explanation

3 braclets at $3 each is $9. If she had $18.50 then you subtract $9 from $18.50 and get

$9.50.

Tags

CCSS.4.MD.A.2