turunan fungsi aljabar

jika f(x) = 3x³-21x²-10x+3 tentukan hasil dari f'(2)

• -55

• -57

• 58

• -58

Answer explanation

f(x)= 3x³-21x²-10x+3

f'(x)= (3 X 3x^3-1) - (2 X 21x^2-1) - (1 X 10x^1-1)

f'(x) = 9x²-42x-10

f'(2) = 9(2²) - 42(2)-10

f'(2) = 36-84-10

f'(2)= -58

• 138

• 137

• 135

• 139

diketahui duatu fungsi f(x) = 2x³-5x+1, maka f'(1)

• -1

• 2

• 1

• 3

Answer explanation

f(x)= 2x³-5x+1

f'(x)= (3 X 2x^3-1) - (1 X 5x^1-1) + 0

f'(x) = 6x²-5

f'(1) = 6(1²)-5

f'(1) = 6-5

f'(1)= 1

dari fungsi f(x) = (7x²-9x-8)² tentukan f'(1)

• 100

• -100

• 10

• -10

Answer explanation

f(x) = (7x²-9x-8)²

f'(x) = 2(7x²-9x-8) (14x-9)

f'(1) = 2(7(1²)-9(1)-8) (14(1)-9)

f'(1) = 2(7-9-8) (14-9)

f'(1) = 2(-10) (5)

f'(1) = -20 x 5

f'(1) = -100

dari fungsi f(x) = (7x²-9x-8)² tentukan nilai dari f'(-1)

• 368

• 386

• -386

• -368

Answer explanation

f(x) = (7x²-9x-8)²

f'(x) = 2(7x²-9x-8) (14x-9)

f'(-1) = 2(7(-1²)-9(-1)-8) (14(-1)-9)

f'(-1) = 2(7+9-8) (-14-9)

f'(-1) = 2(8) (-23)

f'(-1) = 16 x (-23)

f'(-1) = -368

tentukan turunan pertama dari f(x) = (3x²+7x+1)(2x²+6x+5)

• 24x³+96x²+118x+ 41

• 27x³+93x²+108x+41

• 25x³+94x²+128+40

• 24x²+96x³+118x+41

Answer explanation

f(x) = (3x²+7x+1)(2x²+6x+5)

u=3x²+7x+1

u'=6x+7

v =2x²+6x+5

v' = 4x+6

f'(x) = u'v + uv'

f'(x) = (6x+7)(2x²+6x+5) + (3x²+7x+1) (4x+6)

f'(x) = 12x³+36x²+30x+14x²+42x+35 + 12x³+18x²+28x²+42x+4x+6

= 24x³+96x²+118x+41