Exponential/Log Equations

Solve.

9(e^x) - 31 =23

• x = 1.79

• x = 4.21

• x = -3.5

• x = 1.27

Rewrite the exponential as a log.

2^3x+1 = 12

• ln(2)= 3x+1

• log₂(12)= 3x+1

• ln(6)=3x+1

• log₁₂(2)= 3x+1

To solve 8 = 2^5x+7, you would need to re-write 8 as what base?

• 8

• 4

• 2

• Cannot be determined

Solve:

log₂(x + 3)=5

• x=2

• x=29

• x=7

• x=32

Solve:

2log₆(x-8)=2

• 14

• 81/8

• 18

• 9969

Which is the correct way to rewrite,log₆(x-3)= 2, in order to solve.

• 6² = x-3

• 2⁶ = x - 3

• ln(2) = x-3

• e⁶ = x-3

What is the base in the equation

log 8 = 3?

• 8

• 10

• 3

• 1

• 1.11

• 0.27

• 3.70

• 3.60

• 0.31

• 3.27

• 2.58

• 0.87