TES SUMATIF KESETIMBANGAN KIMIA
Quiz
•
Chemistry
•
11th Grade
•
Practice Problem
•
Hard
Ellen Dewi
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15 questions
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1.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Reaksi kesetimbangan dari pembakaran P2O5 :
P4(g) + 5O2(g) ⇌ 2P2O5
Data yang diperoleh pada saat setimbang disajikan pada tabel di samping.
Reaksi berlangsung pada suhu 25oC dalam wadah 1 liter. Tetapan kesetimbangan (Kc) yang tepat adalah…
(0,1).(3,0)5 / (0,4)2
(0,1).(0,4)2 / (3,0)5
(0,4)2.(3,0)5 / (0,1)
(0,4)2.(0,5) / (3,0)5
(0,4)2 / (0,1).(3,0)5
2.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Pada kesetimbangan 2NH3(g) ⇌ N2(g) + 3H2(g) dengan tekanan parsial N2 = 100 atm, H2 = 10 atm dan NH3 = 50 atm. Tetapan kesetimbangan gas (Kp) untuk reaksi tersebut adalah…
0,2
0,4
4
20
40
3.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Perhatikan data reaksi kesetimbangan berikut ini!
(1) N2(g) + 3H2(g) ⇌ 2NH3(g)
(2) 2SO2(g) + O2(g) ⇌ 2SO3(g)
(3) PCl5(g) ⇌ PCl3(g) + Cl2(g)
(4) H2(g) + I2(g) ⇌ 2HI(g)
Pasangan reaksi kesetimbangan yang hasil produknya semakin bertambah jika tekanan diperbesar adalah…
(1) dan (2)
(1) dan (3)
(1) dan (4)
(2) dan (3)
(3) dan (4)
4.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
konsentrasi dan suhu
konsentrasi dan tekanan
volume dan tekanan
volume dan suhu
suhu dan tekanan
5.
MULTIPLE CHOICE QUESTION
5 mins • 1 pt
Perhatikan reaksi: A + B ⇌ C + D. Jika 1 mol A dicampurkan dengan 1 mol B dan pada kesetimbangan terdapat 0,2 mol A, maka tetepan kesetimbangan reaksi tersebut adalah…
0,4
1,6
4
8
16
6.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
Suatu sistem reaksi dalam keadaan setimbang bila…
Reaksi berlangsung dua arah pada waktu bersamaan
Reaksi berlangsung dalam dua arah dalam laju reaksi yang sama
Jumlah mol zat yang ada pada keadaan setimbang selalu sama
Masing-masing zat yang bereaksi sudah habis
Jumlah zat yang terbentuk dalam reaksi sama dengan pereaksi
7.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Tetapan kesetimbangan konsentrasi reaksi: 2BaO2(s) ⇌ 2BaO(s) + O2(g) diberikan oleh…
Kc = [BaO2]2 / [BaO]
Kc = [BaO2]2 / [BaO]2 [O2]
Kc = [BaO2]2 / [BaO]2
Kc = [BaO2]2[O2] / [BaO]2
Kc = [O2]
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