Zero Product Property 2023

Solve for the values of x:
(x + 2)(x - 3) = 0

• { 2, 3 }
• { -2, -3 }
• { 2, 3 }
• { -2, 3 }

Tags

CCSS.HSA-REI.B.4B

Find the zeros.

(2x - 1)(x + 4) = 0

• { 1/2, -4 }

• { 1/2, 4 }

• { 2, -4 }

• { -2, 4 }

Tags

CCSS.HSA-REI.B.4B

Solve and find your x-intercepts:
0=x(x - 6)

• x=0 and x=-6
• x=1 and x=-6
• x=0 and x=6
• x=6

Tags

CCSS.HSA-REI.B.4B

Find all the solutions of

x² + 2x – 3 = 0

• 2 and -1

• -1 and 3

• -2 and 1

• 1 and -3

Tags

CCSS.HSA-REI.B.4B

Find all the solutions of

x² - 10x + 24 = 0

• 6 and 4

• -6 and -4

• 12 and 2

• 8 and 3

Tags

CCSS.HSA-REI.B.4B

What are the zeros of 2x^2 - 7x - 30 = 0?

• -6, 5/2

• -5/2, 6

• 6, 2

• 5, -6

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:

10x^2+ 21x - 10= 0

• { -5/2, -2/5 }

• { -5/2, 2/5 }

• { 5/2, 2/5 }

• { 5/2, -2/5 }

Tags

CCSS.HSA-REI.B.4B

What are the solutions to this equation?

15x^2 -7x - 2=0

• x=5/2,-1/3

• x=1/5,-2/3

• x=1/3,-5/2

• x=2/3,-1/5

Tags

CCSS.HSA-REI.B.4B

Tags

CCSS.HSA-REI.B.4B

• Yes, she factored correctly and then used the zero product property

• No, she didn't factor correctly so the rest of her work is wrong.

• No, she did not set the equation equal to zero before factoring.

Tags

CCSS.HSA-REI.B.4B