Review for Test Logarithms Algebra II Honors

Solve for x using the same base method.
3^x-20 = 27

• 17
• 27
• -7
• 23

Solve: 2^x = 4^x+1

• -2
• 2
• -3
• 3

Solve: 9^8-x = 27^x-3

• x = 5

• x = -5

• x = 1/5

• x = -1/5

Solve for x:
3^2x = 27^{x - 4}

• x = 12
• x = 4
• x = -4
• x = 1

Write in exponential form:

log ₂ 32 = 5

• 2⁵ = 32

• 5² = 32

• 5³² = 2

• 2³² = 5

Write in logarithmic form:
9² = 81

• log ₉ 81 = 2
• log ₂ 81 = 9
• log ₉ 2 = 81
• log ₂ 9 = 81

Rewrite the equation in logarithmic form.

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Using the change of base rule, what is this logarithm equivalent to?

• A
• B
• C
• D