Surface Area of 3D Figures

Surface Area of 3D Figures

8th - 12th Grade

7 Qs

quiz-placeholder

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Surface Area of 3D Figures

Surface Area of 3D Figures

Assessment

Quiz

Mathematics

8th - 12th Grade

Easy

CCSS
7.G.B.6, 6.G.A.4, 7.G.B.4

Standards-aligned

Created by

Valerie Scruggs

Used 1+ times

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7 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Find the surface area of the cube with side lengths 12 m (meters).

144 m2

36 m2

864 m2

216 m2

Tags

CCSS.6.G.A.4

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Find the surface area of the rectangular prism with dimensions 6 in. by 3 in. by 5 in. (inches).

90 in2

180 in2

126 in2

96 in2

Tags

CCSS.7.G.B.6

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Find the surface area of the square pyramid.

429 cm2

389 cm2

441 cm2

377 cm2

Tags

CCSS.7.G.B.6

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Find the surface area of the cylinder with a 
radius of 4 mm and a height of 3 mm (milimeters). 
Use 3.14 for π\pi . Round your answer to the nearest tenth.

175.8 mm2

709.9 mm2

75.4 mm2

100.5 mm2

Tags

CCSS.7.G.B.4

CCSS.7.G.B.6

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Find the surface area of the cone.

Leave your answer in terms of π.

12π m²

16π m²

24π m²

8π m²

6.

MULTIPLE SELECT QUESTION

45 sec • 1 pt

Which two formulas would be used for finding the surface area of a
cylinder and cone?

(choose 2 formulas)

 SA=4πr2SA=4\pi r^2  

 SA=area of the base(s)+area of all lateral facesSA=area\ of\ the\ base\left(s\right)+area\ of\ all\ lateral\ faces 

 SA=area of the bases+2πrhSA=area\ of\ the\ bases+2\pi rh  

 SA=area of the base+πrlSA=area\ of\ the\ base+\pi rl  

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Which general formula would be used for finding the surface area of a 
prism or pyramid?

 SA=4πr2SA=4\pi r^2  

 SA=area of the base(s)+area of all lateral facesSA=area\ of\ the\ base\left(s\right)+area\ of\ all\ lateral\ faces  

 SA=area of the bases+2πrh SA=area\ of\ the\ bases+2\pi rh\   

 SA=area of the base+πrlSA=area\ of\ the\ base+\pi rl