Unit 7 Test: Real Numbers

$$\sqrt[3]{-5}\ \sqrt[3]{3}$$

$$\sqrt[3]{5}\ \sqrt[3]{-3}$$

$$\sqrt[3]{-3}\ \sqrt[3]{-5}$$

$$\sqrt[3]{-15}\ \sqrt[3]{1}$$

$$8\sqrt[]{3}$$

$$3\ +\ \sqrt[]{8}$$

$$8\ -\ \sqrt[]{3}$$

$$8\ +\ \sqrt[]{3}$$

True

False

(x + 4)(x + 2)

(x + 4)(x - 2)

(x - 3)(x + 5)

(x - 4)(x + 2)

$$\frac{6\ +\sqrt[]{\left(-6\right)^2\ -\ 4\left(3\right)\left(8\right)}}{2\left(3\right)}$$

$$\ 6\pm\ \frac{\sqrt[]{\left(-6\right)^2\ -\ 4\left(3\right)\left(8\right)}}{2\left(3\right)}$$

$$\frac{-6\pm\sqrt[]{-6^2-\left(3\right)\left(8\right)}}{2\left(3\right)}$$

$$\frac{6\pm\sqrt[]{\left(-6\right)^2-4\left(3\right)\left(8\right)}}{2\left(3\right)}$$

$$x=11$$

$$x=6,\ x=11$$

no solution

$$1\pm\sqrt[]{3}$$

$$2\pm4\ \sqrt[]{3}$$

no real roots

$$5-3i$$

$$5+17i$$

$$6+61i$$