Form 1 Math 6.1 Part 2

Solve 2r+5 = 9.

Selesaikan 2r+5 = 9.

• r=3

• r=2

• r=1

• r=-2

Solve 2x-6=-12 .

Selesaikan 2x-6=-12

• x =-2

• x=3

• x = -3

• x = 2

Solve x - 12 = 5.

Selesaikan x - 12 = 5.

• x = 17

• x = 7

• x = -17

• x = -7

Solve 27 -3t = 15.

Selesaikan 27 -3t = 15.

• t = 4

• t = -4

• t = 8

• t = -8

Solve 12x -4 = 8.

Selesaikan 12x -4 = 8.

• x = 1

• x = 2

• x = -2

• x = -1

Solve -4y-7 = 8y -79.

Selesaikan -4y-7 = 8y -79.

• y =6

• y =8

• y = -6

• y =-8

• x =51

• x = 15

• x = 20

• x = 25

Solve 6(2x+3) = 10x

Selesaikan 6(2x+3) = 10x.

• x = 18

• x = 9

• x = -9

• x = -18

Jimmy painted his rectangle-shaped bedroom with length x cm and width y cm. The length of the room is twice the width. If the perimeter of the bedroom is 18m, find the value of x.

Jimmy mengecat bilik tidurnya yang berbentuk segi empat tepat dengan panjang x cm dan lebar y cm. Panjang bilik ialah dua kali ganda lebar bilik. Diberi perimeter bilik tidur ialah 18m, cari nilai bagi x.

• 2m

• 4m

• 3m

• 6m

The volume of water in the jug is 1500ml. Fiza pours 5y ml water into the bowl and 3y ml water into the bottle. The remaining water in the jug is 1100ml. What is the difference in volume of water poured into bowls and bottle, in ml?

Isipadu air dalam bekas air ialah 1500 ml. Fiza menuang 5y ml air ke dalam mangkuk dan 3y ml air ke dalam botol. Baki air di dalam bekas air ialah 1100 ml. Apakah perbezaan dalam isipadu air yang dituangkan ke dalam mangkuk dan botol dalam ml?

• 100 ml

• 150 ml

• 200 ml

• 250 ml