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Absolute Value and Literal Equations

Authored by Ashley Fecca

Mathematics

9th Grade

MA covered

Used 8+ times

Absolute Value and Literal Equations
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7 questions

Show all answers

1.

MATCH QUESTION

10 mins • 5 pts

Match the following

Two solutions

x={0,-4}

∣2x+4∣−12=−8\left|2x+4\right|-12=-8

No solution

∣2x−7∣+27=12\left|2x-7\right|+27=12

Two solutions

x={20,0}

3∣4u+6∣−85=−73\left|4u+6\right|-85=-7

One solution

x=2

8∣2x−4∣+12=128\left|2x-4\right|+12=12

Two Solutions

x={5,-8}

−4∣x−10∣=−40-4\left|x-10\right|=-40

Tags

MA.912.AR.4.1

2.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Media Image

Which could be an equation for the graph shown?

∣x−2∣=5\left|x-2\right|=5

∣x−5∣=2\left|x-5\right|=2

∣x+2∣=5\left|x+2\right|=5

∣x+5∣=2\left|x+5\right|=2

Tags

MA.912.AR.4.1

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

You have money in your wallet, but you don’t know the exact amount. When a friend asks you, you say that you have 50 dollars give or take $15.  Write an absolute value equation to model this situation.

∣50+x∣=15\left|50+x\right|=15

∣x+15∣=50\left|x+15\right|=50

∣x−50∣=15\left|x-50\right|=15

∣50−x∣=15\left|50-x\right|=15

Tags

MA.912.AR.4.1

4.

MATH RESPONSE QUESTION

3 mins • 1 pt

Solve for y.

(fully simplify and do not put any spaces in your answer)

15x−5y=3515x-5y=35

y=−7+3xy=-7+3x

Mathematical Equivalence

ON

Tags

MA.912.AR.1.2

5.

DROPDOWN QUESTION

2 mins • 1 pt

The ideal gas law is PV=nRT. Josie wants to find the temperature of the gas. To do this he must isolate T. Solve for the temperature.​ (a)  

Tags

MA.912.AR.1.2

6.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Solve for x.

2x+125=4y\frac{2x+12}{5}=4y

x=20y−12x=20y-12

x=110y+35x=\frac{1}{10}y+\frac{3}{5}

x=10y−12x=10y-12

x=10y−6x=10y-6

Tags

MA.912.AR.1.2

7.

MULTIPLE SELECT QUESTION

3 mins • 1 pt

The formula for perimeter, P of a parallelogram is given below, where length is L, and width is W. What is the result of solving this equation for W? Select all possible answers.

P=2L+2WP=2L+2W

P2−L=W\frac{P}{2}-L=W

P−2L=WP-2L=W

P2+L=W\frac{P}{2}+L=W

2P−L=W2P-L=W

P−2L2=W\frac{P-2L}{2}=W

Tags

MA.912.AR.1.2

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