SDSMT - Exam 2 Review

SDSMT - Exam 2 Review

University

34 Qs

quiz-placeholder

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SDSMT - Exam 2 Review

SDSMT - Exam 2 Review

Assessment

Quiz

Chemistry

University

Medium

NGSS
HS-PS1-1, HS-PS1-2, HS-PS4-1

+2

Standards-aligned

Created by

Kori Cooper

Used 6+ times

FREE Resource

34 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

45 sec • 3 pts

What is the molecular shape and polarity for xenon tetrafluoride?

Square Planar and non-polar

Tetrahedral and non-polar

Trigonal planar and non-polar

Bent and polar

Square planar and polar

Answer explanation

Xenon tetrafluoride (XeF4) has a square planar molecular shape due to the presence of six electron pairs around the central xenon atom, with four bonding pairs and two lone pairs. The symmetric arrangement of the fluorine atoms around the xenon atom results in the cancellation of the individual bond dipoles, making the molecule non-polar.

2.

MULTIPLE CHOICE QUESTION

45 sec • 3 pts

How many polar bonds does CCl4 have in its structure?

0

1

2

3

4

Answer explanation

CCl4 has a tetrahedral structure with carbon at the center and four chlorine atoms surrounding it. Each carbon-chlorine bond is polar due to the difference in electronegativity between carbon and chlorine. Therefore, CCl4 has 4 polar bonds in its structure.

3.

MULTIPLE CHOICE QUESTION

45 sec • 3 pts

According to the octet rule, which of the elements will have a tendency to lose 2 electrons?

Potassium

Sulfur

Oxygen

Strontium

Cesium

Answer explanation

According to the octet rule, elements tend to gain, lose, or share electrons to achieve a stable electron configuration with eight electrons in their outermost shell. Strontium, a Group 2 element, has two valence electrons and will have a tendency to lose 2 electrons to achieve a stable octet configuration.

Tags

NGSS.HS-PS1-1

NGSS.HS-PS1-2

4.

MULTIPLE CHOICE QUESTION

45 sec • 3 pts

What is the ground-state electron configuration of calcium?

1s²2s²2p6

1s²2s²2p 3s²4s8

1s²2s²2p63s²3p64s²

1s²2s²2p63s²

1s²2s²2p63s²3p64s1

Answer explanation

The ground-state electron configuration of calcium is determined by filling the orbitals in order of increasing energy. Calcium has 20 electrons, so the configuration is 1s²2s²2p⁶3s²3p⁶4s². This corresponds to the correct choice, which is 1s²2s²2p⁶3s²3p⁶4s².

Tags

NGSS.HS-PS1-1

5.

MULTIPLE CHOICE QUESTION

45 sec • 3 pts

According to VSEPR theory, the shape of an ammonium ion, NH4+, is most similar to:

Trigonal pyramidal, 109.5°

Trigonal planar, 120°

Bent, 120°

Trigonal pyramidal, 120°

Trigonal planar, 90°

Answer explanation

According to VSEPR theory, the shape of an ammonium ion, NH4+, is most similar to trigonal pyramidal with a bond angle of 109.5°. This is because the central nitrogen atom is surrounded by four hydrogen atoms, forming a tetrahedral arrangement. The trigonal pyramidal shape is a result of the repulsion between the electron pairs, which causes them to spread out as far as possible.

6.

MULTIPLE CHOICE QUESTION

45 sec • 3 pts

Which of the following is true about Fe²+?

Fe²+ is paramagnetic with 0 unpaired electrons

Fe²+ is paramagnetic with 2 unpaired electrons

Fe²+ is paramagnetic with 4 unpaired electrons

Fe²+ is paramagnetic with 5 unpaired electrons

Fe²+ is diamagnetic

Answer explanation

Fe²⁺ is paramagnetic with 4 unpaired electrons because it has an electron configuration of [Ar] 3d⁶. In this configuration, there are 4 unpaired electrons in the 3d orbitals, making it paramagnetic. The other options are incorrect as they either state the wrong number of unpaired electrons or incorrectly classify Fe²⁺ as diamagnetic.

Tags

NGSS.HS-PS1-1

7.

MULTIPLE CHOICE QUESTION

45 sec • 3 pts

According to periodic trends, arrange the following ions, potassium K+, magnesium Mg2+, and aluminum Al³+ in order of increasing ionic size.

K+ < Al³+ < Mg2+

K+ < Mg2+ < Al³+

Al³+ < K+ < Mg2+

Al³+ < Mg2+ < K+

Cannot predict the size trend

Answer explanation

In the periodic table, ionic size decreases across a period and increases down a group. As we move from left to right, potassium (K+), magnesium (Mg2+), and aluminum (Al³+) are in the same period. The correct order of increasing ionic size is Al³+ < Mg2+ < K+, as the charge increases and the number of electrons decreases, making the ion smaller.

Tags

NGSS.HS-PS1-1

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