Motion Test Review

Mr. Stephens kicks a ball with vertical velocity (viy) of 4 m/s and horizontal velocity (vx) of 8 m/s. How do you find the horizontal distance?

• Figure out the time using vy=viy + gt then solve for distance using vx=x/t

• Figure out the time using y=viy(t) + 1/2 g(t^2). Then solve for distance using vx=x/t

• Figure out the time using vx=x/t. Then solve for distance

• Solve for distance using

  x=vt + 1/2g(t^2)

If your given tangential velocity and radius, what can you figure out?

• Vertical acceleration

• Horizontal acceleration

• Centripetal acceleration

• Vertical displacement

If a ball is thrown up in the air at a given velocity, what is the velocity (vi) of the ball as the person catches it (vf) (assume it is caught at the same point as it was thrown)

• vf=x/t

• vf=-vi

• vf=at

• vf=vi

Tags

NGSS.HS-PS2-1

The table shows data from 4 cars. Which car has the fastest acceleration?

• Car A

• Car B

• Car C

• Car D

Tags

NGSS.HS-PS2-1

If I swing a ball on a string, which direction is the centripetal acceleration?

• Outwards

• Upwards

• Downwards

• Inwards towards the center

Two people go running. Runner A covers more distance in the same amount of time as Runner B. Their displacements and direction are the same. Which of the following is true? Select all that apply.

• Runner A has a faster speed than runner B

• Runner B has a faster speed than runner A

• Runner A has a faster velocity than runner B

• Runner B has a faster velocity than runner A.

• Runner A and Runner B have the same Velocity

If you are given the vertical (viy) and horizontal velocity (vx) of a projectile and a horizontal distance (x), how do you find the height (y) at that distance?

• First find the time from vx=x/t, then use

  y=viy(t) + 1/2g(t^2).

• First find the time using vy=viy+gt, then use

  y=viy(t) + 1/2g(t^2).

• You use y=viy(t) + 1/2g(t^2).

• First find the time using

  y=viy(t) + 1/2g(t^2), then use vy=viy+gt

If you are given an initial velocity (vi) and acceleration (a) of a bike rider, how do you figure out the stopping distance (x)?

• You use x=vi(t) + 1/2a(t^2).

• First figure out time using v=x/t, then use

  x=vi(t) + 1/2a(t^2).

• First figure out time using a=v/t, then solve for distance using

  x=vi(t) + 1/2a(t^2).

• First figure out time using a=v/t, then solve for distance using v=x/t

Tags

NGSS.HS-PS2-1