
Motion Test Review
Authored by Jonathan Stephens
Science
12th Grade
NGSS covered
Used 6+ times

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8 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Mr. Stephens kicks a ball with vertical velocity (viy) of 4 m/s and horizontal velocity (vx) of 8 m/s. How do you find the horizontal distance?
Figure out the time using vy=viy + gt then solve for distance using vx=x/t
Figure out the time using y=viy(t) + 1/2 g(t^2). Then solve for distance using vx=x/t
Figure out the time using vx=x/t. Then solve for distance
Solve for distance using
x=vt + 1/2g(t^2)
2.
MULTIPLE CHOICE QUESTION
45 sec • 1 pt
If your given tangential velocity and radius, what can you figure out?
Vertical acceleration
Horizontal acceleration
Centripetal acceleration
Vertical displacement
3.
MULTIPLE CHOICE QUESTION
45 sec • 1 pt
If a ball is thrown up in the air at a given velocity, what is the velocity (vi) of the ball as the person catches it (vf) (assume it is caught at the same point as it was thrown)
vf=x/t
vf=-vi
vf=at
vf=vi
Tags
NGSS.HS-PS2-1
4.
MULTIPLE CHOICE QUESTION
45 sec • 1 pt
The table shows data from 4 cars. Which car has the fastest acceleration?
Car A
Car B
Car C
Car D
Tags
NGSS.HS-PS2-1
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
If I swing a ball on a string, which direction is the centripetal acceleration?
Outwards
Upwards
Downwards
Inwards towards the center
6.
MULTIPLE SELECT QUESTION
1 min • 1 pt
Two people go running. Runner A covers more distance in the same amount of time as Runner B. Their displacements and direction are the same. Which of the following is true? Select all that apply.
Runner A has a faster speed than runner B
Runner B has a faster speed than runner A
Runner A has a faster velocity than runner B
Runner B has a faster velocity than runner A.
Runner A and Runner B have the same Velocity
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
If you are given the vertical (viy) and horizontal velocity (vx) of a projectile and a horizontal distance (x), how do you find the height (y) at that distance?
First find the time from vx=x/t, then use
y=viy(t) + 1/2g(t^2).
First find the time using vy=viy+gt, then use
y=viy(t) + 1/2g(t^2).
You use y=viy(t) + 1/2g(t^2).
First find the time using
y=viy(t) + 1/2g(t^2), then use vy=viy+gt
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