Search Header Logo

PK Module 14: In-Class Activity 1

Authored by Marcy Hernick

Specialty

University

Used 1+ times

PK Module 14: In-Class Activity 1
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

10 questions

Show all answers

1.

FILL IN THE BLANK QUESTION

1 min • 1 pt

Estimate the vancomycin clearance (in L/hr) for a 60-year-old patient who weighs 70 kg and has a creatinine clearance 75 mL/min. Round to the nearest hundredth.

ClVanc (L/hr)= [0.69*(CrCl) + 3.66] x 0.06

Answer explanation

ClVanc (L/hr)= [0.69*(CrCl) + 3.66] x 0.06

ClVanc (L/hr)= [0.69*(75) + 3.66] x 0.06

ClVanc (L/hr)= 3.32

2.

FILL IN THE BLANK QUESTION

1 min • 1 pt

After administration of the loading dose and seven doses (1500 mg each) at 12-hour intervals, plasma vancomycin concentrations are determined to be 44 mg/L (2 hours after the end of the 2-hour infusion) and 16 mg/L at the end of the dosing interval. 

What is the half-life of vancomycin (in hr) in this patient?

Answer explanation

Ke = ln (C1/C2)/t2-t1

K = ln (44mg/L/16mg/L) / (12 - 4 hr) = 0.126 hr-1

t1/2 = 0.693/K = 0.693/0.126 = 5.5 hr

3.

FILL IN THE BLANK QUESTION

2 mins • 1 pt

Calculate the Ke (in hr-1) for a patient that will be initiated on vancomycin using the equation Ke = 0.00083/hr x CrCl + 0.0044 for a 45-year-old man, 5' 10'' tall, weighing 73 kg (IBW = 73 kg), serum creatinine concentration of 1.00 mg/dL.

Ke = 0.00083/hr x CrCl + 0.0044 

Answer explanation

Step 1: Calculate CrCl

CrCl = (140-45)(73)/(72 x 1) = 96.3 mL/min

Step 2: Calculate Ke

Ke = 0.00083/hr x CrCl + 0.0044 = 0.00083/hr(96.3) + 0.0044 = 0.084 hr-1

4.

FILL IN THE BLANK QUESTION

1 min • 1 pt

BW, a 42-year-old man, 5' 10'' tall, weighing 75 kg (IBW = 73 kg), needs to receive a loading dose of vancomycin (25 mg/kg) that will be infused over 2 hours.  

Calculate the loading dose for this patient in mg. For grading purposes do not round.

Answer explanation

LD = 25 mg/kg x 75 kg = 1875 mg

5.

FILL IN THE BLANK QUESTION

1 min • 1 pt

A patient is receiving 750 mg of vancomycin every 12 hours by 1-hour infusion. A steady state trough concentration is measured  0.5 hours before a dose and reported as  12 mg/L. You wish to raise the trough to  17.5 mg/L. 

What dose (rounded to nearest mg) would you suggest if the interval would remain at 12 hours?

Answer explanation

Set up a ratio

Dose1/Conc1 = Dose 2/Conc2

750/12 = Dose2/17.5

Dose = 1094 mg

6.

FILL IN THE BLANK QUESTION

1 min • 1 pt

A patient is receiving 750 mg of vancomycin every 12 hours by 1-hour infusion. A steady state trough concentration is measured  0.5 hours before a dose and reported as  12 mg/L. You wish to raise the trough to  17.5 mg/L. 

What dosing interval should you use if you wish to keep the dose at 750 mg? Do not round

Answer explanation

Taunew = (Css old)/(Css new) x Tau old

Taunew = (12/17.5) x 12 hr

Taunew = 8.2 hours Round to 8 hours

7.

FILL IN THE BLANK QUESTION

2 mins • 1 pt

E.K., a 60-year-old, 50-kg woman with a serum creatinine of 1.0 mg/dL, has been empirically started on 750 mg of vancomycin every 12 hours. A culture indicates that the infection is caused by MRSA with an MIC of 1.0 mg/L. Design a dose in mg to be administered every 24 hr that will produce therapeutic vancomycin concentrations and an AUC24/MIC ≥ 400 for E.K. You have calculated her patient specific K = 0.054 hr-1 and Vd = 34.8 L.

       AUC24/MIC = X24 / (Cl x MIC)

Answer explanation

Step 1: Calculate Cl

Cl = V x K = 34.8 L x 0.054 hr-1 = 1.88 L/hr

Step 2: Calculate Dose

Dose24hr = AUC24/MIC x Cl x MIC

Dose24hr = 400 x 1.88 x 1 = 752 mg

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?