Search Header Logo

PK Module 14: In-Class Activity 1

Authored by Marcy Hernick

Specialty

University

Used 1+ times

PK Module 14: In-Class Activity 1
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

10 questions

Show all answers

1.

FILL IN THE BLANKS QUESTION

1 min • 1 pt

Estimate the vancomycin clearance (in L/hr) for a 60-year-old patient who weighs 70 kg and has a creatinine clearance 75 mL/min. Round to the nearest hundredth.

ClVanc (L/hr)= [0.69*(CrCl) + 3.66] x 0.06

(a)  

Answer explanation

ClVanc (L/hr)= [0.69*(CrCl) + 3.66] x 0.06

ClVanc (L/hr)= [0.69*(75) + 3.66] x 0.06

ClVanc (L/hr)= 3.32

2.

FILL IN THE BLANKS QUESTION

1 min • 1 pt

After administration of the loading dose and seven doses (1500 mg each) at 12-hour intervals, plasma vancomycin concentrations are determined to be 44 mg/L (2 hours after the end of the 2-hour infusion) and 16 mg/L at the end of the dosing interval. 

What is the half-life of vancomycin (in hr) in this patient?

(a)  

Answer explanation

Ke = ln (C1/C2)/t2-t1

K = ln (44mg/L/16mg/L) / (12 - 4 hr) = 0.126 hr-1

t1/2 = 0.693/K = 0.693/0.126 = 5.5 hr

3.

FILL IN THE BLANKS QUESTION

2 mins • 1 pt

Calculate the Ke (in hr-1) for a patient that will be initiated on vancomycin using the equation Ke = 0.00083/hr x CrCl + 0.0044 for a 45-year-old man, 5' 10'' tall, weighing 73 kg (IBW = 73 kg), serum creatinine concentration of 1.00 mg/dL.

Ke = 0.00083/hr x CrCl + 0.0044 

(a)  

Answer explanation

Step 1: Calculate CrCl

CrCl = (140-45)(73)/(72 x 1) = 96.3 mL/min

Step 2: Calculate Ke

Ke = 0.00083/hr x CrCl + 0.0044 = 0.00083/hr(96.3) + 0.0044 = 0.084 hr-1

4.

FILL IN THE BLANKS QUESTION

1 min • 1 pt

BW, a 42-year-old man, 5' 10'' tall, weighing 75 kg (IBW = 73 kg), needs to receive a loading dose of vancomycin (25 mg/kg) that will be infused over 2 hours.  

Calculate the loading dose for this patient in mg. For grading purposes do not round.

(a)  

Answer explanation

LD = 25 mg/kg x 75 kg = 1875 mg

5.

FILL IN THE BLANKS QUESTION

1 min • 1 pt

A patient is receiving 750 mg of vancomycin every 12 hours by 1-hour infusion. A steady state trough concentration is measured  0.5 hours before a dose and reported as  12 mg/L. You wish to raise the trough to  17.5 mg/L. 

What dose (rounded to nearest mg) would you suggest if the interval would remain at 12 hours?

(a)  

Answer explanation

Set up a ratio

Dose1/Conc1 = Dose 2/Conc2

750/12 = Dose2/17.5

Dose = 1094 mg

6.

FILL IN THE BLANKS QUESTION

1 min • 1 pt

A patient is receiving 750 mg of vancomycin every 12 hours by 1-hour infusion. A steady state trough concentration is measured  0.5 hours before a dose and reported as  12 mg/L. You wish to raise the trough to  17.5 mg/L. 

What dosing interval should you use if you wish to keep the dose at 750 mg? Do not round

(a)  

Answer explanation

Taunew = (Css old)/(Css new) x Tau old

Taunew = (12/17.5) x 12 hr

Taunew = 8.2 hours Round to 8 hours

7.

FILL IN THE BLANKS QUESTION

2 mins • 1 pt

E.K., a 60-year-old, 50-kg woman with a serum creatinine of 1.0 mg/dL, has been empirically started on 750 mg of vancomycin every 12 hours. A culture indicates that the infection is caused by MRSA with an MIC of 1.0 mg/L. Design a dose in mg to be administered every 24 hr that will produce therapeutic vancomycin concentrations and an AUC24/MIC ≥ 400 for E.K. You have calculated her patient specific K = 0.054 hr-1 and Vd = 34.8 L.

       AUC24/MIC = X24 / (Cl x MIC)

(a)  

Answer explanation

Step 1: Calculate Cl

Cl = V x K = 34.8 L x 0.054 hr-1 = 1.88 L/hr

Step 2: Calculate Dose

Dose24hr = AUC24/MIC x Cl x MIC

Dose24hr = 400 x 1.88 x 1 = 752 mg

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Microsoft

Continue with Microsoft

or continue with

Facebook

Facebook

Apple

Apple

Others

Others

Already have an account?