50-100 кмф

50-100 кмф

KG

51 Qs

quiz-placeholder

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Assessment

Quiz

Architecture

KG

Easy

Created by

Erkenaz Begalieva

Used 11+ times

FREE Resource

51 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

51. Maple – да  ax2+bx+c=0 теңдеуі қалай шешіледі?

 solve (ax^2 + b*x + c=0, x);

      

      

      

solve (a*x^2 + b*x + c=0, x);

solve (a*x^2 + b*x + c=0);

dsolve (a*x^2 + b*x + c=0, x);

fsolve (ax^2 + bx + c, x)

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

52. Maple – да y=y(x) графигі қалай сызылады?

   

plot [y, x=a .. b];

plot (y, x, ' b-' );

plot (y, x=a .. b);

plot (y; x);

plot (x, y=a .. b);

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

53. Maple – да y=cosx функциясының -3≤ х ≤ 3 аралықтағы графигі қалай сызылады?

    

plot (cosx; x=-3 .. 3);

plot (x, cosx);

plot [cosx, -3<x<3];

plot (cos(x), x=-3 .. 3);

plot [cosx, x=-3 .. 3];

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

54. Maple – да z=f(x,y) графигі қалай сызылады?

     

plot3d (z, x=a .. b, y=c .. d);

plot3 (z, x=a .. b, y=c .. d);

plot (z, x,y,);

plot3d [z; x=a .. b, y=c .. d];

plot3 [z, x=a .. b, y=c .. d];

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

55. Maple – да z=sin(xy) графигі -1<x<1, -1<y<1 аралықта қалай сызылады?

     

plot3 (sin(x*y), x=-1 .. 1, y=-1 .. 1);

plot3d (sin(x*y), x=-1 .. 1, y=-1 .. 1);

plot (sin (xy), x,y);

plot3d [sin(x*y); x=-1 .. 1, y=-1 .. 1];

plot3d [sin(x*y); x=-1 .. 1, y=-1 .. 1];

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

56. Maple – да student бағдарламасы қалай қосылады?

     

With (student);

With (Student);

with (student);

with [student];

With [student];

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

57. Maple – да қос интегралды есептеу функциясы:

    

J: = Doubleint (f(x,y), x=a .. b, y=y1 .. y2);

            value (J);

J: = Dblint (f(x,y), x=a .. b, y=y1 .. y2);

            value (J);

J = Doubleint (f(x,y), x=a .. b, y=y1 .. y2);

            value (J);

J: = Int (f(x,y), x=a .. b, y=y1 .. y2);

            evalf (J);

J: = dbl Int (f(x,y), x=a .. b, y=y1 .. y2);

            evalf (J);

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