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Quadratic Graphs In Vertex Form

Authored by Nabila Fariha

Mathematics

9th Grade

CCSS covered

Used 13+ times

Quadratic Graphs In Vertex Form
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20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Which equation is graphed above?

y=−(x−1)2+4y=-\left(x-1\right)^2+4

y=(x−1)2+4y=\left(x-1\right)^2+4

y=−(x−4)2+1y=-\left(x-4\right)^2+1

y=(x−4)2+1y=\left(x-4\right)^2+1

Tags

CCSS.HSF-IF.C.7A

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Which equations matches the graph above?

h(x)= (x+1)2−4h\left(x\right)=\ \left(x+1\right)^2-4

h(x)=−(x+1)2−4h\left(x\right)=-\left(x+1\right)^2-4

h(x)=(x+4)2−1h\left(x\right)=\left(x+4\right)^2-1

h(x)=−(x+4)2+1h\left(x\right)=-\left(x+4\right)^2+1

Tags

CCSS.HSF-IF.C.7A

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 f(x)=−(x−4)2+1f\left(x\right)=-\left(x-4\right)^2+1  

Choose the correct graph of the equation.

Media Image
Media Image
Media Image
Media Image

Tags

CCSS.HSA.CED.A.2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Which equation matches the  graphed above?

p(x)=(x−1)2+4p\left(x\right)=\left(x-1\right)^2+4

p(x)=(x−4)+1p\left(x\right)=\left(x-4\right)+1

p(x)=−(x+1)2−4p\left(x\right)=-\left(x+1\right)^2-4

p(x)=−(x+4) 2−1p\left(x\right)=-\left(x+4\right)\ ^2-1

Tags

CCSS.HSF-IF.C.7A

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Which equation matches the graph above?

r(x)=−(x+4)2−1r\left(x\right)=-\left(x+4\right)^2-1

r(x)=(x+4)2−1r\left(x\right)=\left(x+4\right)^2-1

r(x)=−(x−4)2+1r\left(x\right)=-\left(x-4\right)^2+1

r(x)=(x−4)2+1r\left(x\right)=\left(x-4\right)^2+1

Tags

CCSS.HSF-IF.C.7A

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Which equation matches the graph?

f(x)=(x−1)2+4f\left(x\right)=\left(x-1\right)^2+4

f(x)=(x+4)2−1f\left(x\right)=\left(x+4\right)^2-1

f(x)=−(x−1)2+4f\left(x\right)=-\left(x-1\right)^2+4

f(x)=−(x+4)2−1f\left(x\right)=-\left(x+4\right)^2-1

Tags

CCSS.HSF-IF.C.7A

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the vertex of the following equation? f(x)=−12(x−5)2+6f\left(x\right)=-\frac{1}{2}\left(x-5\right)^2+6  

 (−5,−6)\left(-5,-6\right)  

 (−5,6)\left(-5,6\right)  

 (5,−6)\left(5,-6\right)  

 (5,6)\left(5,6\right)  

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