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  5. 2 20 24 Radicals And Rational Exponents Notes

2-20-24 Radicals and Rational Exponents Notes

Authored by Eric Smith

Mathematics

11th Grade

CCSS covered

Used 4+ times

2-20-24 Radicals and Rational Exponents Notes
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10 questions

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1.

MATCH QUESTION

1 min • 1 pt

P4. Match the following Properties of Exponents.

(am)n=am⋅n(a^m)^n=a^{m\cdot n}

Power of a Power

a−n=1ana^{-n}=\frac{1}{a^n}

Zero Exponent

(ab)n=(anbn)\left(\frac{a}{b}\right)^n=\left(\frac{a^n}{b^n}\right)

Negative Exponent

a0=1a^0=1

Power of a Quotient

Tags

CCSS.8.EE.A.1

2.

MATCH QUESTION

1 min • 1 pt

P4. Match the following Properties of Exponents.

aman=am−n\frac{a^m}{a^n}=a^{m-n}

Quotient of Powers

am⋅an=am+na^m\cdot a^n=a^{m+n}

Product of Powers

(a⋅b)n=an⋅bn(a\cdot b)^n=a^n\cdot b^n

Power of a Product

Tags

CCSS.8.EE.A.1

3.

DRAG AND DROP QUESTION

1 min • 1 pt

P5 1A-D. I would use the ​ (a)   Property to simply (312)2\left(3^{\frac{1}{2}}\right)^2 to ​ (b)   which shows that 3123^{\frac{1}{2}} =​ (c)   . Generalized that would be a12a^{\frac{1}{2}} =​ (d)   .​

3
Power of a Power

3\sqrt[]{3}  

a\sqrt[]{a}  

Power of a Product
3143^{\frac{1}{4}}
312\sqrt[]{3^{\frac{1}{2}}}
a12\sqrt[]{a^{\frac{1}{2}}}
Radical Power

Tags

CCSS.HSN.RN.A.2

4.

MATCH QUESTION

1 min • 1 pt

Radicals and Rational Exponents are inverses of each other and can be inverted as follows amn=amna^{\frac{m}{n}}=\sqrt[n]{a^m} . Match the exponential terms with their radical equivalent.

x3\sqrt[3]{x}

x32x^{\frac{3}{2}}

x\sqrt[]{x}

x68x^{\frac{6}{8}}

x45\sqrt[5]{x^4}

x12x^{\frac{1}{2}}

x34\sqrt[4]{x^3}

(x12)23\left(x^{\frac{1}{2}}\right)^{\frac{2}{3}}

xxx\sqrt[]{x}

x45x^{\frac{4}{5}}

Tags

CCSS.HSN.RN.A.2

5.

REORDER QUESTION

1 min • 1 pt

Why is x32=xxx^{\frac{3}{2}}=x\sqrt[]{x} ? Reorder the steps to simplify the expression.

x3\sqrt[]{x^3}

x2⋅x\sqrt[]{x^2}\cdot\sqrt[]{x}

x32x^{\frac{3}{2}}

x2⋅x\sqrt[]{x^2\cdot x}

xxx\sqrt[]{x}

Tags

CCSS.HSN.RN.A.2

6.

REORDER QUESTION

1 min • 1 pt

Why is (x4y)12=x2y\left(x^4y\right)^{\frac{1}{2}}=x^2\sqrt[]{y} ? Reorder the steps to simplify the expression.

x2⋅x2⋅y\sqrt[]{x^2\cdot x^2\cdot y}

(x4y)12\left(x^4y\right)^{\frac{1}{2}}

x2⋅x2⋅y\sqrt[]{x^2}\cdot\sqrt[]{x^2}\cdot\sqrt[]{y}

x4y\sqrt[]{x^4y}

x2yx^2\sqrt[]{y}

Tags

CCSS.HSN.RN.A.2

7.

REORDER QUESTION

1 min • 1 pt

Why is 1812=3218^{\frac{1}{2}}=3\sqrt[]{2} ? Reorder the steps to simplify the expression.

2⋅32\sqrt[]{2}\cdot\sqrt[]{3^2}

2⋅32\sqrt[]{2\cdot3^2}

323\sqrt[]{2}

181218^{\frac{1}{2}}

18\sqrt[]{18}

Tags

CCSS.HSN.RN.A.2

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