MODULE 3_IPCC(Summing,DAC,Comparators)

MODULE 3_IPCC(Summing,DAC,Comparators)

University

9 Qs

quiz-placeholder

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MODULE 3_IPCC(Summing,DAC,Comparators)

MODULE 3_IPCC(Summing,DAC,Comparators)

Assessment

Quiz

Education

University

Medium

Created by

Sumathi K

Used 4+ times

FREE Resource

9 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

What is the maximum number of input signals a summing amplifier can have?

No more than two input signals

Two or more input signals

A closed-loop input impedance of infinity

A small open-loop voltage gain

2.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

If the two supply voltages are ±12 V, what is the MPP value of an op amp closest to?

0

-12V

+12V

24V

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

In the Circuit shown,

1. Name of Circuit

2. Output across Node 1

3.Output voltage equation across Node 2 is.

Summer with two inputs

-v1

vout=v1+v2

Subtractor

V1

vout=v2-v1

Subtractor

-V1

vout=v1-v2

Summer with two inputs

v1

vout=v1+v2

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

In the circuit shown,R1 = 1 kΩ, R2 = 2 kΩ, R3 = 3 kΩ, R4 = 4 kΩ, R5 = 5 kΩ, and Rf = 6 kΩ. What is the voltage gain of each channel?

Av1=-6

Av2= -3

Av3= 4.26

Av4= 5

Av1=-6

Av2= -3

Av3= 4.26

Av4= 3.19

Av1= 6

Av2= 3

Av3= -4.26

Av4= -5

Av1= 6

Av2= 3

Av3= -4.26

Av4= -3.19

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The voltage Gain of Averager Circuit with 4 inputs is

1/3

4

1/4

3

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

The Circuit shown is

Subtractor

Summer with 3 inputs

Averager

None

7.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

The maximum and minimum output for Binary Weighted Resistor DAC is

-1.875,0

-0,-1.275

0,1.875

0,-1.875

8.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Binary-weighted D/A converter changes

Analog input to Digital output

Digital input to Analog voltage.

Digital to Digital

None

9.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The output equation for weighted Resistor DAC is

vout = –(v0 + 0.5v1 + 0.25v2 + 0.125v3)

vout = –(v3 + 0.5v2 + 0.25v1 + 0.125v0)

vout = (v3 + 0.5v2 + 0.25v1 + 0.125v0)

vout = –(v3 + 0.5v2 + 0.25v1 + 0.25v0)