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Q3W6 - FEB. 29, 2024 - FCT, Permutation & Combination

Authored by Amalia Nogales

Mathematics

9th - 12th Grade

CCSS covered

Used 1+ times

Q3W6 - FEB. 29, 2024 - FCT, Permutation & Combination
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10 questions

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1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the counting principle in fundamental counting techniques?

The counting principle states that if there are m ways to do one thing and n ways to do another, then there are m - n ways to do both things together.

The counting principle states that if there are m ways to do one thing and n ways to do another, then there are m + n ways to do both things together.

The counting principle states that if there are m ways to do one thing and n ways to do another, then there are m / n ways to do both things together.

The counting principle states that if there are m ways to do one thing and n ways to do another, then there are m * n ways to do both things together.

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Calculate 5 factorial.

120

30

100

25

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

How many permutations can be made from the letters A, B, C, D?

12

6

24

18

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

In how many ways can a committee of 3 be chosen from a group of 10 people?

15

6

50

120

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Solve the following application problem: In how many ways can a president, vice president, and treasurer be chosen from a group of 10 people?

120

30

90

45

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the probability of drawing 2 red balls and 1 blue ball from a bag containing 5 red balls and 3 blue balls?

The probability is (5C2 * 3C1) / 8C3 = (10 * 3) / 56 = 30/56 = 5/28

The probability is (5C2 * 3C1) / 8C3 = (10 * 3) / 56 = 30/56 = 15/28

The probability is (5C2 * 3C1) / 8C3 = (10 * 3) / 56 = 30/56 = 1/28

The probability is (5C2 * 3C1) / 8C3 = (10 * 3) / 56 = 30/56 = 15/28 + 1

Tags

CCSS.HSS.CP.B.9

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

A lock has 4 dials, each labeled with the digits 0-9. How many possible combinations are there if each digit can only be used once?

24

362880

5040

120

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