What is the value of p for the series ∑(1/n^2) to converge?
Calculus P-Series Test (AI generated)

Quiz
•
Mathematics
•
9th - 12th Grade
•
Medium
Cristen Charnley
Used 2+ times
FREE Resource
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
p = 0
p = 1
p > 1
p < 1
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Determine whether the series ∑(1/n^3) converges or diverges.
Converges to 0
Diverges
Converges to 1
Converges
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Identify the value of p for the series ∑(1/n^4) to converge.
2
3
4
5
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Does the series ∑(1/n^1/2) converge or diverge? Explain your answer.
Converges
Remains constant
Multiplies by 2
Diverges
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Apply the p-series test to determine the convergence of the series ∑(1/n^3/2).
The series ∑(1/n^3/2) converges.
The series ∑(1/n^3/2) diverges.
The series ∑(1/n^3/2) oscillates.
The p-series test cannot be applied to the given series.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Explain the concept of p-series in calculus.
A p-series in calculus is a series of the form ∑(1/n^p), where n ranges from 1 to 10 and p is a constant. It converges if p > 2 and diverges if p <= 2.
A p-series in calculus is a series of the form ∑(1/n^p), where n ranges from 1 to infinity and p is a variable. It converges if p > 1 and diverges if p <= 1.
A p-series in calculus is a series of the form ∑(1/n^p), where n ranges from 1 to infinity and p is a constant. It converges if p > 1 and diverges if p <= 1.
A p-series in calculus is a series of the form ∑(1/n^p), where n ranges from 1 to infinity and p is a constant. It converges if p > 0 and diverges if p <= 0.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Solve the problem using the p-series test: Determine the convergence of the series ∑(1/n^5).
The series ∑(1/n^5) oscillates.
The series ∑(1/n^5) converges.
The series ∑(1/n^5) diverges.
The series ∑(1/n^5) is undefined.
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