Ôn tập Gk2 TOÁN 10 NH 2023-2024

$$f\left(x\right)=3x^2+2x-5$$

$$f\left(x\right)=\frac{1}{2}x^2-2x$$

$$f\left(x\right)=4-x^2$$

$$f\left(x\right)=mx^2-4x\ \ \left(m\in R\right)$$

Δ=9, S={-1;2}

Δ=3, S={-1;2}

Δ=9, S={-2;1}

Δ=3, S={-2;1}

$$a<0,\ \Delta<0$$

$$a<0,\Delta>0$$

$$a<0,\ \Delta\le0$$

$$a>0,\Delta\le0$$

$$S=\left(-\infty;1\right)\cup\left(3;+\infty\right)$$

$$S=\left(-\infty;1\right]\cup\left[3;+\infty\right)$$

$$S=\left(1;3\right)$$

$$S=\left[1;3\right]$$

$$2x-3>1$$

$$2x^2-3x+1<0$$

$$x^2-3x+2=0$$

$$x^2-2x\ge y^2$$

$$-\frac{1}{2}\le x\le4$$

$$x<-\frac{1}{2}$$ hoặc $$x>4$$

$$-\frac{1}{2}<x<4$$

$$x\le-\frac{1}{2}$$ hoặc $$x\ge4$$

$$f\left(x\right)=2x^2+5x+2$$

$$f\left(x\right)=-2x^2+5x-2$$

$$f\left(x\right)=x^2+x+2$$

$$f\left(x\right)=-x^2+x-2$$

x = - 1

x = 0

$$x=\frac{5}{3}$$

x = 3

$$x=0$$

$$x=1$$

$$x=0,x=1$$

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