用角度制來表示 − π 3 -\frac{\pi}{3} − 3 π

− 60 ° -60\degree − 6 0 °

− 30 ° -30\degree − 3 0 °

− 300 ° -300\degree − 3 0 0 °

− 120 ° -120\degree − 1 2 0 °

用弧度制來表示 420 ° 420\degree 4 2 0 °

13 6 π \frac{13}{6}\pi 6 1 3 π

任意角的三角函數--練習1

Authored by sio iris

Mathematics

9th - 12th Grade

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MULTIPLE CHOICE QUESTION

1 min • 1 pt

用角度制來表示
$-\frac{\pi}{3}$

$-30\degree$

$-300\degree$

$-60\degree$

$-120\degree$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

用弧度制來表示
$420\degree$

$\frac{7}{3}\pi$

$\frac{13}{6}\pi$

$\frac{\pi}{3}$

$\frac{9}{4}\pi$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

求弧長。

12π cm

15π cm

39.375 cm

14π cm

MULTIPLE CHOICE QUESTION

1 min • 1 pt

有向角規定"逆時針"轉的為

正角

負角

MULTIPLE CHOICE QUESTION

1 min • 1 pt

如圖, $P\left(-4,3\right)$ 為 $\theta$ 終邊上的一點,則 $\sin\theta=?$

$\frac{3}{5}$

$\frac{-4}{5}$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

如圖, $P\left(-4,3\right)$ 為 $\theta$ 終邊上的一點,則 $\cos\theta=?$

$\frac{3}{5}$

$\frac{-4}{5}$

MULTIPLE CHOICE QUESTION

1 min • 1 pt

若 $\theta$ 為第二象限角,則 $\sin\theta$ 為

正的

負的

MULTIPLE CHOICE QUESTION

1 min • 1 pt

若 $\theta$ 為第三象限角,則 $\cos\theta$ 為

正的

負的

MULTIPLE CHOICE QUESTION

1 min • 1 pt

若 $\theta$ 為第四象限角,則 $\tan\theta$ 為

正的

負的

10.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

$\sin180^0=?$

-1

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任意角的三角函數--練習1

用角度制來表示 −π3-\frac{\pi}{3}−3π​

用弧度制來表示 420°420\degree420°

求弧長。

有向角規定"逆時針"轉的為

如圖, P(−4,3)P\left(-4,3\right)P(−4,3) 為 θ\thetaθ 終邊上的一點,則 sin⁡θ=?\sin\theta=?sinθ=?

如圖, P(−4,3)P\left(-4,3\right)P(−4,3) 為 θ\thetaθ 終邊上的一點,則 cos⁡θ=?\cos\theta=?cosθ=?

若 θ\thetaθ 為第二象限角,則 sin⁡θ\sin\thetasinθ 為

若 θ\thetaθ 為第三象限角,則 cos⁡θ\cos\thetacosθ 為

若 θ\thetaθ 為第四象限角,則 tan⁡θ\tan\thetatanθ 為

sin⁡1800=?\sin180^0=?sin1800=?

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用角度制來表示
$-\frac{\pi}{3}$

用弧度制來表示
$420\degree$

如圖, $P\left(-4,3\right)$ 為 $\theta$ 終邊上的一點,則 $\sin\theta=?$

如圖, $P\left(-4,3\right)$ 為 $\theta$ 終邊上的一點,則 $\cos\theta=?$

若 $\theta$ 為第二象限角,則 $\sin\theta$ 為

若 $\theta$ 為第三象限角,則 $\cos\theta$ 為

若 $\theta$ 為第四象限角,則 $\tan\theta$ 為

$\sin180^0=?$