AP Physics 2 Ultimate Review

Quiz
•
Physics
•
11th Grade
•
Hard
+9
Standards-aligned
KELLY DOYLE
Used 10+ times
FREE Resource
84 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Container A has a sample of gas A, while container B has a sample of gas B. The atoms of both gases currently have the same average speed, but the molecules of gas B have a greater molar mass than the molecules of gas A. What can be concluded about the temperatures?
Gas A & gas B are the same temperature
Gas A has a greater temperature
Gas B has a greater temperature
Cannot be determined without knowing the number of molecules in each container
Answer explanation
Temperature is directly proportional to kinetic energy.
K = (3/2) kBT
Whichever gas has more kinetic energy will have a greater temperature.
K = 0.5mv2
The speeds (v) is the same, but gas B has a greater mass, so it will have more kinetic energy and therefore a greater temperature.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Two capacitors are wired in series as shown. The circuit has reached steady state. A student measures the charge on the 4 μF and finds it a non-zero +Q0.
How does Kirchhoff's loop rule apply to this circuit?
It doesn't, it only applies to circuits with batteries
The two capacitors will have potential differences equal in magnitude
The voltage drop across the 2 μF will be twice that of the voltage drop across the 4 μF
There is a voltage drop in the wire itself equal to the voltage drop in the capacitors
Capacitors do not have voltage drops across them
Answer explanation
Kirchhoff's law applies to all circuits, whether or not they have a battery.
In in this loop, the potential differences must add up to zero. The trick here is that each capacitor will have the same magnitude of voltage drop, but in opposite directions.
At steady state, the wire will have no significant voltage drop, even if it did have some natural resistance. This is because there is no significant current flow in the wire at steady state.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Two capacitors are wired in series as shown. The circuit has reached steady state. A student measures the charge on the 4 μF and finds it a non-zero +Q0.
What is the magnitude of charge on the 2 μF capacitor?
0.5Q0
Q0
2Q0
4Q0
0
Answer explanation
Due to Kirchhoff's loop rule, these two capacitors have equal and opposite voltage drops.
V4 = V2
(Q0 / C4) = (Q2 / C2)
(Q0 / 4 μF) = (Q2 / 2 μF)
Q0 = 2Q2
Q2 = 0.5Q0
Another way to think of it. The 2 μF capacitor has half the "room" for electrons as compared to the 4 μF. That is essentially what capacitance is: it's a reflection on the capacitor's ability to hold electrons.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A convex mirror has a focal located 0.3 m behind it. If you place an object 0.5 m in front of the mirror, where is the image formed?
0.2 in front of the mirror
0.32 m in front of the mirror
0.19 m behind the mirror
0.45 behind the mirror
Answer explanation
For convex mirrors, the focal is located BEHIND the mirror, where light rays cannot actually go. For this reason, the focal in convex mirrors must be NEGATIVE when doing the math.
(1 / 0.5) + (1 / si) = (1 / −0.3)
(1 / si) = −0.5333
si = −0.1875 m
The si is negative, which tells us this image forms behind the mirror.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
The current through resistor X is measured to be 4 A and the current through resistor Y is 1 A. What is the current through resistor Z?
4 A
3 A
1 A
Cannot be determined without knowing more values
Answer explanation
The junction law says that the total current going into a junction is the amount of current coming out of the junction.
There are 4 amps before the junction. Then, one of the branches has 1 amp. So, the other branch must have 3 amps!
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
A, B, C, and D represent processes by which an electron drops to a lower orbit. Which process will result in the greatest frequency of photon emitted?
A
B
D
They all emit the same frequency
Answer explanation
The larger the energy drop, the greater the energy of photon released. Process D has the electron falling from E = -2 eV to E = -10 eV. This is a change of energy of -8 eV, meaning the photon released has 8 eV of energy.
Energy is directly proportional to frequency for photons (E = hf). More energy means more frequency.
Tags
NGSS.HS-PS4-3
7.
FILL IN THE BLANK QUESTION
1 min • 1 pt
A chef grabs a hot pan and burns his hand. By what primary process did the heat transfer into his hand?
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