GRAPHING A PARABOLA (CONICS)

GRAPHING A PARABOLA (CONICS)

11th Grade

20 Qs

quiz-placeholder

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GRAPHING A PARABOLA (CONICS)

GRAPHING A PARABOLA (CONICS)

Assessment

Quiz

Mathematics

11th Grade

Hard

Created by

Ralph Jay Magsalay

Used 8+ times

FREE Resource

20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the standard equation of the parabola with vertex

 (8,2) and directrix x=10.5?\left(-8,2\right)\ and\ directrix\ x=-10.5?  

 (y2)2=10(x+8)\left(y-2\right)^2=10\left(x+8\right)  

 (y2)2=10(x+8)\left(y-2\right)^2=-10\left(x+8\right)  

 (y8)2=10(x+2)\left(y-8\right)^2=10\left(x+2\right)  

 (y8)2=10(x+2)\left(y-8\right)^2=-10\left(x+2\right)  

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the standard equation of the parabola with vertex  (11,7) and directrix  y =4?\left(11,7\right)\ and\ directrix\ \ y\ =4?  

 (x11)2=12(y7)\left(x-11\right)^2=12\left(y-7\right)  

 (y11)2=12(x7)\left(y-11\right)^2=12\left(x-7\right)  

 (x7)2=12(y11)\left(x-7\right)^2=12\left(y-11\right)  

 (y7)2=12(x11)\left(y-7\right)^2=12\left(x-11\right)  

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the standard equation of the parabola with vertex
 

 (2,4) and focus (1,4)?\left(2,-4\right)\ and\ focus\ \left(-1,-4\right)?  

 (y+4)2=12(x2)\left(y+4\right)^2=-12\left(x-2\right)  

 (y+4)2=12(x2)\left(y+4\right)^2=12\left(x-2\right)  

 (x2)2=12(y+4)\left(x-2\right)^2=12\left(y+4\right)  

 (x2)2=12(y+4)\left(x-2\right)^2=-12\left(y+4\right)  

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the standard equation of the parabola with vertex  (1,9) and focus (3,9)?\left(1,-9\right)\ and\ focus\ \left(-3,-9\right)?  
 

 (y+9)2=16(x1)\left(y+9\right)^2=-16\left(x-1\right)  

 (y+9)2=16(x1)\left(y+9\right)^2=16\left(x-1\right)  

 (x1)2=16(y+9)\left(x-1\right)^2=-16\left(y+9\right)  

 (x1)2=16(y+9)\left(x-1\right)^2=16\left(y+9\right)  

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the standard equation of the parabola with vertex  focus(11,7) and directrix x=1?focus\left(11,7\right)\ and\ directrix\ x=1?  
 

 (y7)2=20(x6)\left(y-7\right)^2=20\left(x-6\right)  

 (y7)2=20(x6)\left(y-7\right)^2=-20\left(x-6\right)  

 (x6)2=20(y11)\left(x-6\right)^2=20\left(y-11\right)  

 (x6)2=20(y11)\left(x-6\right)^2=-20\left(y-11\right)  

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the standard equation of the parabola with vertex  focus(11,7) and directrix y=4?focus\left(11,7\right)\ and\ directrix\ y=4?  
 

 (y5.5)2=6(x11)\left(y-5.5\right)^2=-6\left(x-11\right)  

 (y5.5)2=6(x11)\left(y-5.5\right)^2=6\left(x-11\right)  

 (x11)2=6(y5.5)\left(x-11\right)^2=-6\left(y-5.5\right)  

 (x11)2=6(y5.5)\left(x-11\right)^2=6\left(y-5.5\right)  

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Based on the graph, what is the standard equation of the parabola?

(y+4)2=12(x2)\left(y+4\right)^2=12\left(x-2\right)

(y+4)2=12(x2)\left(y+4\right)^2=-12\left(x-2\right)

(x2)2=12(y+4)\left(x-2\right)^2=12\left(y+4\right)

(x2)2=12(y+4)\left(x-2\right)^2=-12\left(y+4\right)

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