Quiz about 4-1直角三角形的邊角關係

Question 1

$$ an\ 45\degree=?$$

Accepted Answer

$$1$$

Answer

$$\sqrt[]{3}$$

Answer

$$\frac{\sqrt[]{2}}{2}$$

Answer

$$\frac{\sqrt[]{3}}{2}$$

Question 2

tan $$ heta$$

Accepted Answer

$$\frac{24}{7}$$

Answer

$$\frac{7}{24}$$

Answer

$$\frac{7}{25}$$

Answer

$$\frac{24}{25}$$

Question 3

sinA =

Accepted Answer

$$\frac{8}{17}$$

Answer

$$\frac{15}{17}$$

Answer

$$\frac{8}{15}$$

Answer

$$\frac{15}{8}$$

Question 4

Question 4.

Accepted Answer

$$\frac{3\ \sqrt[]{3}}{2}$$

Answer

$$\frac{2\ \sqrt[]{2}}{3}$$

Answer

$$\frac{3}{2}$$

Answer

$$\frac{\sqrt[]{3}}{2}$$

Question 5

$$\sin^2⁡40°+\sin^2⁡50°+\cos⁡^240°+\cos⁡^250°$$

Accepted Answer

2

Answer

1

Answer

$$\frac{3}{2}$$

Answer

3

Question 6

$$ an20\degree imes\cos20\degree$$

Accepted Answer

$$\sin20\degree$$

Answer

$$\cos^220\degree$$

Answer

$$\frac{\cos^220\degree}{\sin20\degree}$$

Answer

$$\frac{1}{\sin20\degree}$$

Question 7

$$\cos74\degree-\cos14\degree$$

Accepted Answer

$$\sin16\degree-\sin76\degree$$

Answer

$$\cos60\degree$$

Answer

$$\frac{\sqrt[]{3}}{2}$$

Answer

$$\sin16\degree-\sin16\degree$$

Question 8

$$\frac{\sin69\degree}{\cos21\degree}-\frac{\cos48\degree}{\sin42\degree}$$

Accepted Answer

0

Answer

1

Answer

$$ an48\degree- an6\degree$$

Answer

$$ an90\degree-\frac{1}{ an90\degree}$$

Question 9

$$\left(\sin15\degree-\cos15\degree\right)^2$$

Accepted Answer

$$1-2 imes\sin15\degree imes\cos15\degree$$

Answer

0

Answer

1

Answer

$$1-\sin15\degree$$

Question 10

Question 10.

Accepted Answer

2

Answer

$$\frac{1}{2}$$

Answer

3

Answer

$$\frac{1}{3}$$

Question 11

Question 11.

Accepted Answer

$$\frac{3}{8}$$

Answer

$$-\frac{8}{3}$$

Answer

$$-\frac{3}{8}$$

Answer

$$\frac{3}{16}$$

4-1直角三角形的邊角關係

20 questions

在30°－60°－90° 三角形中，三個邊長比為：

在45°－45°－90° 三角形中，三個邊長比為：

三角函數的英文是？

sinA =

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