
Solving Equations Quiz
Authored by David Escobedo
Mathematics
12th Grade
TEKS covered
Used 4+ times

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10 questions
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1.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
x = 42
x = 58
x = 50
x = 8
Answer explanation
To solve the equation x + 8 = 50 using the addition principle, we need to isolate x. Subtract 8 from both sides to get x = 42.
Tags
TEKS.MATH.6.10A
2.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
x = -18
x = -50
x = -20
x = -16
Answer explanation
To solve the equation -34 = x - 16 using the addition principle, we need to isolate x. Add 16 to both sides to get x = -34 + 16. Therefore, x = -18.
Tags
TEKS.MATH.6.10A
3.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
x = -43
x = -7
x = -25
x = -18
Answer explanation
To solve the equation -25 = x - 18 using the addition principle, we need to isolate x. Add 18 to both sides to get x = -25 + 18. Therefore, x = -7.
Tags
TEKS.MATH.6.10A
4.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
x = 9
x = 15
x = 5
x = 3
Answer explanation
To solve the equation 3 + x = 12 using the addition principle, we need to isolate x. Subtract 3 from both sides to get x = 9.
Tags
TEKS.MATH.6.10A
5.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
x = \frac{5}{11}
x = \frac{9}{11}
x = \frac{1}{11}
x = \frac{3}{11}
Answer explanation
To solve the equation, isolate x by subtracting 2/11 from both sides. x = 7/11 - 2/11 = 5/11.
Tags
TEKS.MATH.6.10A
6.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
x = 2.7
x = 3.7
x = 6.4
x = 10.1
Answer explanation
Subtract 3.7 from both sides to isolate x. 6.4 - 3.7 = x. Therefore, x = 2.7.
Tags
TEKS.MATH.6.10A
7.
MULTIPLE CHOICE QUESTION
3 mins • 1 pt
x = \frac{1}{2}
x = \frac{2}{5}
x = \frac{1}{5}
x = \frac{3}{10}
Answer explanation
To solve for x, first subtract 1/10 from both sides to isolate x. x = 3/5 - 1/10 = 6/10 - 1/10 = 5/10 = 1/2.
Tags
TEKS.MATH.6.10A
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