Open Up - Grade 7 - Mathematics - Unit 3 - Lesson 10

Open Up - Grade 7 - Mathematics - Unit 3 - Lesson 10

7 Qs

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Open Up - Grade 7 - Mathematics - Unit 3 - Lesson 10

Open Up - Grade 7 - Mathematics - Unit 3 - Lesson 10

Assessment

Quiz

Math

Hard

7.G.4

Standards-aligned

Created by

Quizizz Content

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7 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

For each problem, decide whether the circumference of the circle or the area of the circle is most useful for finding a solution.A car’s wheels spin at 1000 revolutions per minute. The diameter of the wheels is 23 inches. You want to know how fast the car is travelling.
Circumference
Area

Tags

7.G.4

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

For each problem, decide whether the circumference of the circle or the area of the circle is most useful for finding a solution.A circular kitchen table has a diameter of 60 inches. You want to know how much fabric is needed to cover the table top.
Circumference
Area

Tags

7.G.4

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

For each problem, decide whether the circumference of the circle or the area of the circle is most useful for finding a solution.A circular puzzle is 20 inches in diameter. All of the pieces are about the same size. You want to know about how many pieces there are in the puzzle.
Circumference
Area

Tags

7.G.4

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

For each problem, decide whether the circumference of the circle or the area of the circle is most useful for finding a solution.You want to know about how long it takes to walk around a circular pond.
Circumference
Area

Tags

7.G.4

5.

OPEN ENDED QUESTION

3 mins • 1 pt

While in math class, Priya and Kiran come up with two ways of thinking about the proportional relationship shown in the table. Both students agree that they can solve the equation 5k = 1750 to find the constant of proportionality.Priya says, “I can solve this equation by dividing 1750 by 5.”Kiran says, “I can solve this equation by multiplying 1750 by \frac{1}{5}What value of k would each student get using their own method?

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7.G.4

6.

OPEN ENDED QUESTION

3 mins • 1 pt

While in math class, Priya and Kiran come up with two ways of thinking about the proportional relationship shown in the table. Both students agree that they can solve the equation 5k = 1750 to find the constant of proportionality.Priya says, “I can solve this equation by dividing 1750 by 5.”Kiran says, “I can solve this equation by multiplying 1750 by \frac{1}{5} How are Priya and Kiran's approaches related?

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7.G.4

7.

OPEN ENDED QUESTION

3 mins • 1 pt

While in math class, Priya and Kiran come up with two ways of thinking about the proportional relationship shown in the table. Both students agree that they can solve the equation 5k = 1750 to find the constant of proportionality.Priya says, “I can solve this equation by dividing 1750 by 5.”Kiran says, “I can solve this equation by multiplying 1750 by \frac{1}{5}Explain how each student might approach solving the equation \frac{2}{3}k=50.

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7.G.4