Equation Skills Quiz

Solve.
(2x - 3) / 4  = 9

• x = 24

• x = 12

• x = 17.5

• x = 19.5

Answer explanation

To solve the equation, first multiply both sides by 4 to get 2x - 3 = 36. Then, add 3 to both sides to get 2x = 39. Finally, divide by 2 to find x = 19.5, which is the correct answer.

Tags

CCSS.7.EE.B.4A

Tags

CCSS.7.EE.B.4A

4a-2=3a-7

• a=-9

• a=-2

• a=7

• a=-5

Answer explanation

Subtract 3a from both sides to get a-2=-7. Then add 2 to both sides to find a=-9. Therefore, the correct choice is a=-9.

Answer explanation

Subtract 2x from both sides to isolate x. This gives x = 4. However, upon further simplification, x = 2 is the correct solution.

Answer explanation

To solve the equation, combine like terms: 4y - 2y = 2y. Then, subtract 3 from both sides to get 2y = 6. Finally, divide by 2 to find y = 3. Therefore, the correct answer is y = 3.

Tags

CCSS.7.EE.B.4A

Answer explanation

To solve for z, first distribute 2 to both terms inside the parentheses: 6z - 8 = 10. Then, isolate z by adding 8 to both sides and dividing by 6, giving z = 2.

Tags

CCSS.7.EE.B.4A

Answer explanation

Subtract 2x from both sides to get 3x - 3 = 6. Then, add 3 to both sides to find x = 3. Therefore, x = 3 is the correct answer.

Translate the word problem into an equation and solve: "Three times a number decreased by 7 is equal to 11."

Answer explanation

To translate the word problem into an equation, we have 3x - 7 = 11. Solving for x, we get x = 6. Therefore, the correct answer is x = 6.

Tags

CCSS.7.EE.B.4A

Answer explanation

To solve the equation, first distribute the 4 on the left side: 4x + 8 = 3x + 10. Then, isolate x by moving the 3x to the left side: 4x - 3x = 10 - 8. Simplify to get x = 2. Therefore, x = 2 is the correct choice.

Tags

CCSS.8.EE.C.7B

Answer explanation

To solve the equation, combine like terms: 7a - 2a = 5a. Then, the equation becomes 5a + 5 = 20. Subtract 5 from both sides to get 5a = 15. Finally, divide by 5 to find a = 3. Therefore, the correct answer is a = 3.

Tags

CCSS.7.EE.B.4A