CTLG

CTLG

11th Grade

10 Qs

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CTLG

CTLG

Assessment

Quiz

Mathematics

11th Grade

Practice Problem

Hard

Created by

Trang Quỳnh

Used 1+ times

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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Trong các công thức sau, công thức nào ĐÚNG?

cos(ab)=cosa.sinb+sina.cosb\cos\left(a-b\right)=\cos a.\sin b+\sin a.\cos b

sin(ab)=sina.cosbcosa.sinb\sin\left(a-b\right)=\sin a.\cos b-\cos a.\sin b

sin(a+b)=sina.cosbcosa.sinb\sin\left(a+b\right)=\sin a.\cos b-\cos a.\sin b

cos(a+b)=cosa.cosb+sina.sinb\cos\left(a+b\right)=\cos a.\cos b+\sin a.\sin b

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Chọn khẳng định SAI trong các khẳng định sau:


cos(a+b)=cosa.cosb+sina.sinb\cos\left(a+b\right)=\cos a.\cos b+\sin a.\sin b

sin(a+b)=sina.cosb+cosa.sinb\sin\left(a+b\right)=\sin a.\cos b+\cos a.\sin b

sin(ab)=sina.cosbcosa.sinb\sin\left(a-b\right)=\sin a.\cos b-\cos a.\sin b

cos2a=12sin2a\cos2a=1-2\sin^2a

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt


 cos37π12=?\cos\frac{37\pi}{12}=?  

 6+24\frac{\sqrt{6}+\sqrt{2}}{4}  

 624\frac{\sqrt{6}-\sqrt{2}}{4}  

 6+24-\frac{\sqrt{6}+\sqrt{2}}{4}  

 264\frac{\sqrt{2}-\sqrt{6}}{4}  

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Cho sinx=35\sin x=\frac{3}{5} với  π2<x<π\frac{\pi}{2}<x<\pi . Khi đó  tan(x+π4)=?\tan\left(x+\frac{\pi}{4}\right)=?   

 17-\frac{1}{7}  

 7-7  

 17\frac{1}{7}  

 77   

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 Đẳng thức nào KHÔNG ĐÚNG với mọi x ?

 cos2x=1+cos2x2\cos^2x=\frac{1+\cos2x}{2}  

 cos2x=12sin2x\cos2x=1-2\sin^2x  

 sin2x=2.sinx.cosx\sin2x=2.\sin x.\cos x  

 sin2x=1+cos2x2\sin^2x=-\frac{1+\cos2x}{2}  

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Mệnh đề nào sau đây ĐÚNG?


cos2a=cos2asin2a\cos2a=\cos^2a-\sin^2a

cos2a=sin2acos2a\cos2a=\sin^2a-\cos^2a

cos2a=12cos2a\cos2a=1-2\cos^2a

cos2a=2sin2a1\cos2a=2\sin^2a-1

7.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Nếu sinx+cosx=12\sin x+\cos x=\frac{1}{2} thì sin2x\sin2x bằng bao nhiêu?

 34\frac{3}{4}  

 38-\frac{3}{8}  

 22\frac{\sqrt{2}}{2}  

 34-\frac{3}{4}  

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