Exponential Growth and Decay Problem Solving

Exponential Growth and Decay Problem Solving

Assessment

Interactive Video

Created by

Olivia Brooks

Mathematics

8th - 12th Grade

Hard

Miss Smith's math tutorial covers exponential growth and decay through real-life word problems. The video explains how to use the exponential formula to solve problems involving population growth, juice consumption decline, car depreciation, and bank savings growth. Each example demonstrates how to identify the starting point, rate of change, and time period to calculate the final value. The tutorial emphasizes understanding the context of the problem and correctly interpreting the results.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for exponential growth and decay?

y = a * (b^x)

y = a / (b^x)

y = a + bx

y = a - bx

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If a population doubles every 10 years, what is the rate of change (b) in the formula?

20

0.5

2

10

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the population after 50 years if it starts at 3,000 and doubles every 10 years?

96,000

48,000

24,000

12,000

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of 'a' in the exponential formula when discussing the initial population of 3,000 people?

3,000

1.5

6,000

10

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you convert a percentage to a decimal for use in the exponential formula?

Divide by 100

Multiply by 100

Add 1

Subtract 1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For a value that depreciates 10% every 6 months, how many periods are there in 7 years?

28

7

10

14

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the approximate amount of juice consumed per person in 2010 if it decreases by 4.1% each year from 16.5 gallons in 1981?

4.9 gallons

5 gallons

16.5 gallons

12 gallons

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How much is a car worth after 7 years if it depreciates 10% every 6 months, starting at $35,000?

$8,006.88

$17,500

$28,000

$35,000

9.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After 12 years, how much money is in Barbara's savings account if it started with $100 and accrues 9% interest annually?

$281.27

$200

$300

$150

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does 'compounded annually' mean in terms of interest accrual?

Interest is calculated every 6 months

Interest is calculated yearly

Interest is calculated daily

Interest is calculated monthly

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