STS MATH LANJUT XII

$$(x-2)^2+(y+5)^2=4$$

$$(x-2)^2+(y+5)^2=16$$

$$(x+2)^2+(y-5)^2=4$$

$$(x+2)^2+(y-5)^2=16$$

$$(x-2)^2+(y-5)^2=16$$

$$(x-1)^2+(y+1)^2=\sqrt{2}$$

$$(x+1)^2+(y-1)^2=\sqrt{2}$$

$$(x-1)^2+(y+1)^2=2\sqrt{2}$$

$$(x+1)^2+(y-1)^2=2$$

$$(x+1)^2+(y-1)^2=8$$

(-3, 1) dan r = 2

(-3,1) dan r = 4

(3, -1) dam r = 2

(3, -1) dan r = 4

(3, -1) dan r = 6

(2, 1)

(-1. 3)

(5, 1)

(-4, 1)

(3, 2)

Garis memotong lingkaran di dua titik

Garis menyinggung lingkaran

Garis tidak memotong lingkaran

Garis tidak menyinggung lingkaran

Garis menempel lingkaran

3x - 5y + 1 = 0

3x + 3y + 5 = 0

3x – y - 5 = 0

3x + y + 5 = 0

3x - y + 5 = 0

Y = 2x – 5

Y = - 2x – 5

Y = - 2x + 5

$$y=\frac{1}{2}x+5$$

$$y=\frac{\text{1}}{\text{2}}x-5$$

4x + 3y + 25 = 0

4x + 3y – 25 = 0

4x – 3y – 25 = 0

3x + 4y – 25 = 0

3x + 4y + 25 = 0

4

6

9

12

16

(– 2, 5)

(2, 5)

(-2, 1)

(-6., 5)

(9, -2)